Hooke's Law and Force in a Slingshot

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SUMMARY

This discussion focuses on the application of Hooke's Law in analyzing the mechanics of a slingshot. The participants confirm that the rubber band is stretched to the left, obeys Hooke's Law, and that the spring constant (k) can be determined from the slope of the provided force-displacement graph. They derive the speed of a 46g rock released from a 29cm stretch using the conservation of energy principle, leading to the formula V = √(K*X/m), where K is the spring constant, X is the displacement, and m is the mass of the rock.

PREREQUISITES
  • Understanding of Hooke's Law and its mathematical representation (Fsp = -kΔx)
  • Knowledge of spring constant (k) and its significance in elastic materials
  • Familiarity with energy conservation principles in physics
  • Basic algebra for manipulating equations and solving for variables
NEXT STEPS
  • Learn how to calculate spring constants from force-displacement graphs
  • Study the conservation of energy in mechanical systems
  • Explore the implications of Hooke's Law in real-world applications
  • Investigate the relationship between mass, displacement, and velocity in elastic collisions
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators and anyone interested in the practical applications of Hooke's Law in everyday scenarios.

mcnealymt
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Homework Statement


A 46g rock is placed in a slingshot and the rubber band is stretched. The force of the rubber band on the rock is shown by the graph in the figure(Figure 1) .

http://session.masteringphysics.com/problemAsset/1073689/4/10.P37.jpg


a)Is the rubber band stretched to the right or to the left?
b)Does this rubber band obey Hooke's law?
c)What is the rubber band’s spring constant k?
d)The rubber band is stretched 29cm and then released. What is the speed of the rock?

Homework Equations



Fsp= -kΔx

The Attempt at a Solution



a) Left because the displacement is negative and therefore the Fsp must be positive?
b) Yes, it obeys Hooke's Law because as the displacement increases, the amount of force does?
c) Isn't it just the slope of the given graph?
d) Honestly not sure where to begin.
 
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mcnealymt said:
a)Is the rubber band stretched to the right or to the left?
b)Does this rubber band obey Hooke's law?
c)What is the rubber band’s spring constant k?
d)The rubber band is stretched 29cm and then released. What is the speed of the rock?

The Attempt at a Solution



a) Left because the displacement is negative and therefore the Fsp must be positive?
b) Yes, it obeys Hooke's Law because as the displacement increases, the amount of force does?
c) Isn't it just the slope of the given graph?
d) Honestly not sure where to begin.

a) and b) are correct but b) can be amended as " the force is proportional to the displacement and in opposition to it and hence obeys the law".

For c) yes it is the slope.

For d) are you aware of the expression for energy stored in the band as a function of the stretch(x)? If yes, try conservation of energy. If no, try deriving the expression using
Energy stored=∫F.dx for the band and then use conservation of energy.
 
Alright, thank you. It turns out I forgot to convert the mass to kg.

This is what I got:

Spring Potential Energy= Kinetic Energy
Us (initial)=KE (Final)
.5kx^2= .5mv^2

V= Square root of ( K*X/m)

k= spring constant
X= change in displacement
m= mass of the rock
 
mcnealymt said:
V= Square root of ( K*X/m)

You mean square root of Square root of ( K*(X^2)/m) right? That was unintentional on your part I guess.

Anyway, Enjoy Physics.:smile:
 
Lol, fail on my part... thanks Sunil Simha.
 

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