How Accurate is Differential Approximation for Fourth Roots?

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Homework Help Overview

The discussion revolves around approximating the fourth root of 17 using differential calculus. Participants explore the accuracy of their approximations and the methods involved in using differentials.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants attempt to apply the differential formula to approximate ##\sqrt[4]{17}##, noting the initial calculations and resulting errors. Some suggest that higher-order terms may improve accuracy, while others discuss the implications of using larger values for ##\Delta x##.

Discussion Status

The conversation includes multiple attempts to approximate the fourth root, with some participants providing insights on improving accuracy. There is acknowledgment of the limitations of the current approach, and suggestions for further exploration of the topic are present.

Contextual Notes

Participants note that the approximation may not be accurate due to the relatively large value of ##\Delta x## compared to the base value of 17. There is also a mention of a small error in the differential formula used by one participant.

Karol
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Homework Statement


Approximate ##~\sqrt[4]{17}~## by use of differential

Homework Equations


Differential: ##~dy=f(x)~dx##

The Attempt at a Solution


$$y=\sqrt[4]{x},~~dy=\frac{1}{4}x^{-3/4}=\frac{1}{4\sqrt[4]{x^3}}$$
$$\sqrt[4]{16}=2,~~dx=1,~~dy=\frac{1}{4\sqrt[4]{x^2}}\cdot 1=0.149$$
$$\sqrt[4]{17}=2.031$$
The error is too big
 
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Karol said:

Homework Statement


Approximate ##~\sqrt[4]{17}~## by use of differential

Homework Equations


Differential: ##~dy=f(x)~dx##

The Attempt at a Solution


$$y=\sqrt[4]{x},~~dy=\frac{1}{4}x^{-3/4}=\frac{1}{4\sqrt[4]{x^3}}$$
$$\sqrt[4]{16}=2,~~dx=1,~~dy=\frac{1}{4\sqrt[4]{x^2}}\cdot 1=0.149$$
$$\sqrt[4]{17}=2.031$$
The error is too big

Nevertheless, your result is correct.

If you want better accuracy you need to take additional, higher order terms (2nd derivatives, maybe 3rd derivatives,etc).
 
Thank you Ray
 
Karol said:

Homework Statement


Approximate ##~\sqrt[4]{17}~## by use of differential

Homework Equations


Differential: ##~dy=f(x)~dx##

The Attempt at a Solution


$$y=\sqrt[4]{x},~~dy=\frac{1}{4}x^{-3/4}=\frac{1}{4\sqrt[4]{x^3}}$$
$$\sqrt[4]{16}=2,~~dx=1,~~dy=\frac{1}{4\sqrt[4]{x^2}}\cdot 1=0.149$$
$$\sqrt[4]{17}=2.031$$
The error is too big
Here is how I would write things.
##f(x + \Delta x) \approx f(x) + df \approx f(x) + f'(x) \Delta x = x^{1/4} + \frac 1 4 x^{-3/4} \Delta x##
When ##x = 16## and ##\Delta x = 1##, we have
##\sqrt[4]{16 + 1} \approx 16^{1/4} + \frac 1 4 \frac 1 {16^{3/4}} \cdot 1 = 2 + \frac 1 32 = 2.03125##
By calculator, ##\sqrt[4]{17} \approx 2.03054##. Since ##\Delta x = 1## is relatively large in comparison to x = 17, the approximation using differentials isn't all that accurate. If ##\Delta x## were smaller, the approximation would be better.
 
Thank you Mark44
By the way, how do i copy your names here, i write them again. when i pause the mouse on your name it becomes a pointer and there is no option to copy
 
Karol said:
Thank you Mark44
By the way, how do i copy your names here, i write them again. when i pause the mouse on your name it becomes a pointer and there is no option to copy
Just hit the 'Reply' button on the lower right of the post. You may also hite the 'Quote' button , also on the lower right.
BTW, small mistake: dy=f'(x)dx , not dy=f(x)dx , unless f(x)=f'(x).
 
Thanks, but i mean i want to copy your name, WWGD, to here, instead of looking and typing it. i usually thank every one that answered my question
 
Karol said:
Thanks, but i mean i want to copy your name, WWGD, to here, instead of looking and typing it. i usually thank every one that answered my question
Maybe you can just use the 'Like' button as a means of thanking.
 

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