How Accurate Is Our Estimation of the World’s Ocean Mass?

Click For Summary
SUMMARY

The discussion centers on estimating the mass of water in the world's oceans using the density of seawater (1025 kg/m³) and the Earth's radius (6.3 x 106 m). The initial calculation suggested a seawater volume of 2.1 x 1018 m³, leading to a mass of 2.1 x 1021 kg. Participants clarified that two-thirds refers to the surface area of the Earth, not its total volume, and recommended incorporating the average depth of the ocean for a more accurate estimate.

PREREQUISITES
  • Understanding of basic geometry and volume calculations
  • Knowledge of seawater density (1025 kg/m³)
  • Familiarity with Earth's dimensions, specifically its radius (6.3 x 106 m)
  • Concept of surface area versus volume in spherical objects
NEXT STEPS
  • Research the average depth of the world's oceans for accurate volume calculations
  • Learn about the formula for calculating the volume of a sphere and its applications
  • Explore the impact of varying seawater density on mass estimations
  • Investigate the relationship between surface area and volume in spherical shells
USEFUL FOR

Students in physics or environmental science, educators teaching oceanography, and anyone interested in geophysical calculations related to Earth's oceans.

hasan_researc
Messages
166
Reaction score
0

Homework Statement



"Estimate the mass of water in all the World’s oceans."


Homework Equations



I know the following:
Two-thirds of the Earth is sea.
The density of seawater is 1025 kg/m3.
Radius of the Earth = 6.3*106m.


The Attempt at a Solution



Let's assume that the Earth's crust is a spherical shell that has a thickness of 0.001 times the radius of the earth.
So, the volume of the crust = (4\pir2)(router-rinner) = 3.1*1018 m3.
So, volume of seawater = 2.1*1018 m3.
So, mass of seawater = 2.1*1021 kg.

Is the answer reasonable? How might I improve it?
 
Physics news on Phys.org
no no, ~2/3 of the SURFACE of the Earth is ocean. much much less of the entire Earth is ocean. I'd recommend using the average depth of the ocean, and the surface area of the earth.
 
"no no, ~2/3 of the SURFACE of the Earth is ocean. much much less of the entire Earth is ocean.": I am reading the 'surface' as the crust (or the outer layer) of the earth. I think that's what I have used in the calculation, not ~2/3 of the entire volume of the earth.

" I'd recommend using the average depth of the ocean, and the surface area of the earth. ":
I think that's what I did above.

I'd be glad if you could offer some genuine help.
 
hasan_researc said:
I'd be glad if you could offer some genuine help.
Very sorry! I took, "Two-thirds of the Earth is sea" to mean that you thought that 'two-thirds of the Earth was sea.' I clearly should have known you meant something completely different.

Your numbers look good; your radius is a little big, but your density a little small (for sea-water), you should be within a factor of two.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
3K
Replies
4
Views
15K
Replies
6
Views
11K
Replies
7
Views
3K
  • · Replies 17 ·
Replies
17
Views
6K
  • · Replies 12 ·
Replies
12
Views
3K
Replies
6
Views
7K
  • · Replies 23 ·
Replies
23
Views
5K
Replies
3
Views
3K
  • · Replies 9 ·
Replies
9
Views
28K