1. The problem statement, all variables and given/known data A lost shipping container is found resting on the ocean floor and completely submerged. The container is 6.3 m long, 2.1 m wide, and 2.6 m high. Salvage experts attach a spherical balloon to the top of the container and inflate it with air pumped down from the surface. When the balloon's radius is 1.8 m, the shipping container just begins to rise towards the surface. What is the mass of the container? Ignore the mass of the balloon and the air within it. Do not neglect the buoyant force exerted on the shipping container by the water. The density of seawater is 1025 kg/m3. Container L = 6.3 m w = 2.1 m h = 2.6 m V = ? Balloon / Air r = 1.8 m p = 1.29 kg / m3 V = FB = Water p = 1025 kg / m3 FB = 2. Relevant equations Archimedes' Principle FB = Wfluid Vcontainer = L * w * h Vballoon = 4/3 [tex]\pi[/tex]r3 p = m / v F = ma 3. The attempt at a solution First I found the volumes for the container and the balloon. Vcontainer = L * w * h Vcontainer = 6.3 * 2.1 * 2.6 Vcontainer = 34.398 m3 Vballoon = 4/3 [tex]\pi[/tex]r3 Vballoon = 4/3 [tex]\pi[/tex]1.83 Vballoon = 24.429 I then tried to find the buoyant force of the air. FB = Wair FB = mg FB = pVg FB = 1.29 * 24.429 * 9.8 FB = 308.83 N And then for the sea water. FB = Wwater FB = mg FB = pVg FB = 1025 * 34.398 * 9.8 FB = 345527.91 N After this, I used newton's 2nd law... F = ma m = F / a m = FBair + FBwater / g m = 308.83 N + 345527.91 N / 9.80 m/s2 m = 35289 kg ----> 3.5 * 104 kg But.......this appears to be wrong...Um...thoughts? Thanks!