How Is Force Calculated on a Submerged Object's Window at Extreme Depths?

[iseidthat]

Homework Statement

In this problem, please make sure to use the density of seawater = 1025 kg/m3.

The bottom of the Mariana Trench, located in the Pacific Ocean, is about 11,000 m below the ocean's surface, making it the deepest ocean depth on Earth.
If an underwater vehicle were exploring the region, at a depth of 10550 m,

a.) What force would the water exert on the vehicle's circular observation window, which has a radius of 0.1 m?

Homework Equations

P= pgh

The Attempt at a Solution

P=pgh=1025 x 9.81 x 10550= 1.06 e8 Pa

i don't really get how the radius relates...
and if I'm suppose to find the buoyant force, how do i find it without the mass or volume?

 

[Doc Al]

How does pressure relate to force?

 

[PhanthomJay]

Homework Statement

In this problem, please make sure to use the density of seawater = 1025 kg/m3.

The bottom of the Mariana Trench, located in the Pacific Ocean, is about 11,000 m below the ocean's surface, making it the deepest ocean depth on Earth.
If an underwater vehicle were exploring the region, at a depth of 10550 m,

a.) What force would the water exert on the vehicle's circular observation window, which has a radius of 0.1 m?

Homework Equations

P= pgh

The Attempt at a Solution

P=pgh=1025 x 9.81 x 10550= 1.06 e8 Pa

i don't really get how the radius relates...
and if I'm suppose to find the buoyant force, how do i find it without the mass or volume?

You calculated the pressure correctly; the problem wants not the buoyant force, but rather, the force of the water pressure on the window. How is force and pressure related?

 

[iseidthat]

well
F=P x A...but i don't have the area...
i know radius is 0.1 m, but i don't know the other dimensions.

 

[iseidthat]

ohhh its a circular window! ahah i misread it.
so the area of a circle :
A=pi r^2=pi(.1m)^2=.031416 m^2

so F= 1.06 e 8 x .031416 =3.33 e 6

mmmk thanks :)