That only works when the variations in the endpoints are small. The integral over a small interval is approx. the function value at a point in the interval times the width of the interval.
But why is the variation due to ends points L(t2)Δt2 - L(t1)Δt1 rather than L(t2 +Δt2) - L(t1 +Δt1) . Makes more sense if it is L(t2 +Δt2) - L(t1 +Δt1)
But why is the variation due to ends points L(t2)Δt2 - L(t1)Δt1 rather than L(t2 +Δt2) - L(t1 +Δt1) . Makes more sense if it is L(t2 +Δt2) - L(t1 +Δt1)
If the deltas are small it makes no difference where you evaluate the function within the small interval.