How calcule this integral: x*e^x^2/e^x^2 + 1?

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    Integral
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Discussion Overview

The discussion revolves around the calculation of the integral of the function \( \frac{x e^{x^2}}{e^{x^2} + 1} \). Participants are seeking assistance with the integration process, particularly focusing on substitution methods.

Discussion Character

  • Homework-related

Main Points Raised

  • One participant requests help with calculating the integral, specifically asking for guidance on the steps involved.
  • Another participant suggests a substitution \( u = e^{x^2} + 1 \) as a potential approach to simplify the integral.
  • A subsequent reply asks for clarification on the next steps after the substitution is proposed.
  • One participant emphasizes the need to show effort in the problem-solving process and questions what to do after making a substitution.
  • Another participant provides the derivative of the substitution, stating that \( du = e^{x^2} dx \) is the normal outcome of the substitution.
  • A later reply corrects a previous statement regarding the derivative rule, indicating that the derivative of \( e^{f(x)} \) involves the derivative of \( f(x) \) multiplied by \( e^{f(x)} \).
  • Finally, a participant asks for further clarification on what \( du \) equals after applying the derivative rule.

Areas of Agreement / Disagreement

The discussion does not reach a consensus, as participants express uncertainty about the next steps in the integration process and the application of the substitution method.

Contextual Notes

Participants have not fully resolved the mathematical steps following the proposed substitution, and there are indications of missing assumptions regarding the integration technique.

Father20
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How calcule this integral: x*e^x^2/e^x^2 + 1

Please help me.
 
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Father20 said:
How calcule this integral: x*e^x^2/e^x^2 + 1

Please help me.

Let [tex]u=e^{x^2}+1[/tex]
 
and further? Thank you for your help.
 
You need to show some effort. What do you do after making a u-substitution?
 
du= e^x^2 dx normally.
 
Not quite.

[tex]\frac{d}{dx}e^{f(x)}=f'(x)\cdot e^{f(x)}[/tex]
 
But after this, what's then. Sorry for my questions.
 
Well first, apply the rule I just showed you. What does du equal?
 

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