How can checking your answer prevent losing marks on an exam question?

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SUMMARY

The discussion focuses on the importance of verifying answers in mathematics exams to avoid losing marks due to careless mistakes. A participant initially calculated z = -3 - 15i but later corrected it to z = 2 + 3i by equating real and imaginary parts after substituting z and its conjugate. The conversation emphasizes that checking answers by substituting them back into the original equation is a crucial strategy in exam settings. Participants shared personal experiences highlighting the impact of arithmetic errors on their scores.

PREREQUISITES
  • Understanding of complex numbers and their conjugates
  • Ability to manipulate equations involving real and imaginary parts
  • Familiarity with simultaneous equations
  • Basic exam strategies for mathematics
NEXT STEPS
  • Learn techniques for solving complex equations involving conjugates
  • Study methods for checking solutions in algebraic problems
  • Explore common arithmetic errors in mathematics and how to avoid them
  • Review strategies for effective time management during exams
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Students preparing for mathematics exams, educators teaching complex numbers, and anyone looking to improve their problem-solving accuracy in mathematical contexts.

CheesyPeeps
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Homework Statement


I've used z* to mean z conjugate.
Given the equation z + 2iz* = 8 + 7i, express z in the form a + ib.

From SQA Advanced Higher Mathematics 2005 Exam Paper

Homework Equations


n/a

The Attempt at a Solution


I substituted a+ib and its conjugate in for z and z*, which, after some rearranging, gave me z =-3-15i.
I am not sure if that's the correct answer, and I'm a bit suspicious of how straightforward that method was. The question is worth 4 marks, which seems an awful lot for not much work. Have I missed something?
 
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Hi CheezePeeps:

I got a different answer than you did. I agree the problem is straight forward, but careless mistakes are possible. Please post the details of how you arrived at your answer?

Regards,
Buzz
 
Thanks for your reply!

I looked back over my initial working, and there were definitely some careless mistakes made from rushing through the steps too quickly!
I redid the problem, making sure that I didn't cut any corners or make arithmetic errors, and I got z = 2 + 3i.
To get z = 2 + 3i, I equated the real and imaginary parts of the equation after substituting in a+ib and a-ib, then used simultaneous equations to get the values of a and b.
 
Hi CheezePeeps:

That is the answer I got.

Regards,
Buzz
 
CheesyPeeps said:

Homework Statement


I've used z* to mean z conjugate.
Given the equation z + 2iz* = 8 + 7i, express z in the form a + ib.

From SQA Advanced Higher Mathematics 2005 Exam Paper

Homework Equations


n/a

The Attempt at a Solution


I substituted a+ib and its conjugate in for z and z*, which, after some rearranging, gave me z =-3-15i.
I am not sure if that's the correct answer, and I'm a bit suspicious of how straightforward that method was. The question is worth 4 marks, which seems an awful lot for not much work. Have I missed something?

One strategy that you should always use is to check your answer by substituting it into the original equation to see if it "works". In an exam setting that is all you can do: no appeal to outside help.

In your case you would soon see that your answer is incorrect.
 
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Ray Vickson said:
One strategy that you should always use is to check your answer by substituting it into the original equation to see if it "works". In an exam setting that is all you can do: no appeal to outside help.

In your case you would soon see that your answer is incorrect.

Good advice! I lost 7 marks out of 100 on the paper this question was from, and most of them were due to arithmetic errors that could've been avoided by using that strategy, so thank you!
 

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