How can get the eigenvalues of the two spin entangle

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SUMMARY

The discussion focuses on calculating the eigenvalues of a Hamiltonian for two entangled spins, represented by the equation H=J(σ^1·σ^2 + σ^2·σ^1) + B(σ^1_z + σ^2_z). The Pauli matrices σ^i (i=1,2) are utilized to describe the spins, with J as the exchange constant. The user seeks a detailed representation of how to solve the Hamiltonian to obtain the four eigenvalues corresponding to the triplet states (S_tot = 1, M = +1, 0, -1) and the singlet state (S_tot = 0, M = 0).

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nicxm
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there is a equation for two spins in entangled
Hamiltonian: H=J([tex]\vec{\sigma}^1\cdot\vec{\sigma}^2+\vec{\sigma}^2\cdot\vec{\sigma}^1[/tex])+B([tex]\vec{\sigma}^1_z+\vec{\sigma}^2_z[/tex])

where [tex]\vec{\sigma}^i=(\sigma^i_x,\sigma^i_y,\sigma^i_z)[/tex] are the pauli matrics for the ith (i=1,2) spin. J is the exchange constant ,

My difficulties: how can we solve the Hamiltonian to get the four eigenvalues?

thank you for helping me, and i want a detail reprentation.
 
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Simply let H act on your four different spin states.

The triplet S_tot = 1, M=+1,0,-1

and the singlet S_tot = 0, M =0

Good luck
 

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