How can I convert degrees to grades using a conversion factor?

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SUMMARY

The discussion focuses on converting angles from degrees to grades using a specific conversion factor. The conversion formula established is $1^{\circ}=\frac{10^g}{9}$ and $1^g=\frac{9^{\circ}}{10}$. To convert degrees to grades, one must express the degree measure as a product involving $1^\circ$ and then substitute it with the conversion factor. For example, converting $45^\circ$ results in $50^g$. Conversely, to convert grades to degrees, the process involves representing grades as a product of $1^g$ and substituting accordingly, as shown with $30^g$ converting to $27^\circ$.

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Drain Brain
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please explain to me how can I utilize this conversion factor to convert degrees to grades

the book says,

$90^{\circ}=100^g$

$\therefore$ $1^{\circ}=\frac{10^g}{9}$ and $1^g=\frac{9^{\circ}}{10}$ - I don't know how to use this in actual convertion please help.

 
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Drain Brain said:
I don't know how to use this in actual convertion
Suppose you want to convert an angle measure from degrees to grades.

Step 1: Represent the number of degrees as a product by 1. For example, rewrite $45^\circ$ as $45\cdot1^\circ$.

Step 2: Replace $1^\circ$ by the quantity from your post, i.e., $\left(\frac{10}{9}\right)^g$. In this example,you get $45\cdot\left(\frac{10}{9}\right)^g=50^g$.

Similarly, to convert from grades to degrees, represent $x^g$ as $x\cdot1^g$ and then replace $1^g$ by $\left(\frac{9}{10}\right)^\circ$. For example,
\[
30^g=30\cdot1^g= 30\cdot\left(\frac{9}{10}\right)^\circ =27^\circ.
\]
 

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