MHB How can I convert degrees to grades using a conversion factor?

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To convert degrees to grades, use the conversion factor where $90^{\circ} = 100^g$, leading to $1^{\circ} = \frac{10^g}{9}$ and $1^g = \frac{9^{\circ}}{10}$. Start by rewriting the angle in degrees as a product, such as $45^\circ = 45 \cdot 1^\circ$. Replace $1^\circ$ with $\left(\frac{10}{9}\right)^g$, resulting in $45 \cdot \left(\frac{10}{9}\right)^g = 50^g$. For converting grades to degrees, represent $x^g$ as $x \cdot 1^g$ and substitute $1^g$ with $\left(\frac{9}{10}\right)^\circ$, yielding the conversion.
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please explain to me how can I utilize this conversion factor to convert degrees to grades

the book says,

$90^{\circ}=100^g$

$\therefore$ $1^{\circ}=\frac{10^g}{9}$ and $1^g=\frac{9^{\circ}}{10}$ - I don't know how to use this in actual convertion please help.

 
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Drain Brain said:
I don't know how to use this in actual convertion
Suppose you want to convert an angle measure from degrees to grades.

Step 1: Represent the number of degrees as a product by 1. For example, rewrite $45^\circ$ as $45\cdot1^\circ$.

Step 2: Replace $1^\circ$ by the quantity from your post, i.e., $\left(\frac{10}{9}\right)^g$. In this example,you get $45\cdot\left(\frac{10}{9}\right)^g=50^g$.

Similarly, to convert from grades to degrees, represent $x^g$ as $x\cdot1^g$ and then replace $1^g$ by $\left(\frac{9}{10}\right)^\circ$. For example,
\[
30^g=30\cdot1^g= 30\cdot\left(\frac{9}{10}\right)^\circ =27^\circ.
\]
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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