How can I derive the equation for calculating pump horsepower?

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SUMMARY

The equation for calculating pump horsepower (Hp) is derived as follows: Hp = Q(gpm) * Δp(psi) / 1714, where Q represents the volumetric flow rate in gallons per minute and Δp denotes the pressure in psi. The derivation involves converting horsepower to foot-pounds per minute and accounting for the weight of water, where 1 gallon of water equals 8.33 pounds. The relationship between pump head (H) and pressure is established using the formula Δp = H * 144 in²/ft² / 62.4 lbs/ft, leading to the final equation for horsepower.

PREREQUISITES
  • Understanding of fluid dynamics principles
  • Familiarity with units of measurement (gpm, psi, ft-lb/min)
  • Basic knowledge of pump systems and their components
  • Ability to perform unit conversions and dimensional analysis
NEXT STEPS
  • Study the principles of fluid dynamics in pump systems
  • Learn about the relationship between pump head and pressure
  • Explore the implications of horsepower calculations in pump efficiency
  • Investigate different types of pumps and their performance metrics
USEFUL FOR

Engineers, mechanical designers, and anyone involved in the design or analysis of pumping systems will benefit from this discussion, particularly those focused on optimizing pump performance and efficiency calculations.

mhzq007
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hi everyone can anyone please give me a clue of how to derive this equation

Hp= Q(gpm)* Δp(psi)/1714

Q is volumetric flow rate
Δp is pressure
 
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mhzq007 said:
hi everyone can anyone please give me a clue of how to derive this equation

Hp= Q(gpm)* Δp(psi)/1714

Q is volumetric flow rate
Δp is pressure

1 HP = 33000 ft-lb/min.

1 gal. water = 8.33 lbs

for water, Δp = H * 144 in^{2}/ft^{2} / 62.4 lbs / ft,
where H is the pump head in feet of water

So

HP = Q*H / 33000 = [Q gal/min * 8.33 lbs / gal * H feet of water * Δp * (144/62.4 lbs / ft^{2})] / 33000

HP = [Q * Δp * 8.33 * (62.4/144)] / 33000 = Q * Δp / 1714
 

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