How can I determine the order of N in this rate law lab?

  • Thread starter Thread starter Ritzycat
  • Start date Start date
  • Tags Tags
    Chem Lab Laws
Click For Summary
SUMMARY

The discussion revolves around determining the order of the reactant N in the rate law for the reaction 5(HSO3) + 2(IO3) -> I2 + 5(SO4) + H2O + 3H. The participant calculated the rate of disappearance of bisulfate using the formula (Volume of bisulfate / Time) and derived the order of m as 0.95 from multiple trials. To find the order of N, they averaged the values obtained from various trials, ultimately concluding with an average order of N at approximately 3.05 after substituting the value of m.

PREREQUISITES
  • Understanding of chemical kinetics and rate laws
  • Familiarity with the iodine clock reaction
  • Ability to perform calculations involving ratios and averages
  • Knowledge of experimental design for chemical reactions
NEXT STEPS
  • Study the derivation of rate laws in chemical kinetics
  • Learn about the iodine clock reaction and its applications
  • Explore methods for determining reaction orders from experimental data
  • Investigate the impact of varying concentrations on reaction rates
USEFUL FOR

Chemistry students, laboratory technicians, and educators involved in teaching or learning about chemical kinetics and reaction mechanisms.

Ritzycat
Messages
170
Reaction score
4

Homework Statement


Hello. I need help with a lab today that involves rate laws.

The goal of this lab is to show the concentration of the reactant ions in this equation

5(HSO3) + 2(IO3) -> I2 + 5(SO4) + H2O + 3H.

We did several trials of varying amounts of the ions and calculated the rate of disappearance of the bisulfate for each trial.

nbdInpN.png


I got the rate of disappearance from taking the volume of the bisulfate and dividing it by the time it took (for the blue color to show, this is supposedly an "iodine clock", thus meaning that the bisulfate had all been used up)

Then I used this formula to calculate the order. I did this for every trial that had the same volume of bisulfate.

This one is using trials 1 and 2.
(20 mL/10 mL)^m (10 mL/10 mL)^n = (.85 mL/s /.46 mL/s)

Sorry if that's hard to read. I did that with trials 1 and 2, 2 and 3, 1 and 3, 1 and 4, and 1 and 5. All the ones that had the same value in my table for the B. That may be confusing. After I did that we averaged the orders of the ones we got. My average order for "m" was 0.95.

But now I am stumped on what to do next. How do I find the value for the order of N so I can find the Rate Law? Is there a way I can find the value of N if none of them are the same for each of the experiments? I cannot seem to be able to find the N because none of the iodate initial concentrations are the same value from experiment to experiment. Some guidance on what to do next would be helpful.

Homework Equations


Rate law

Thank you all for your time, always good help here at physicsforums.
 
Physics news on Phys.org
I figured it out. Just plugged in value of M and did it all for the Ns, the average N came out to be about 3.05.
 

Similar threads

Replies
1
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 2 ·
Replies
2
Views
3K