Reaction Rate Experiment - Concentration

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SUMMARY

The discussion centers on a reaction rate experiment involving potassium iodate (KIO3) and hydrogen sulfite ion (HSO3(-)). Participants conducted trials to determine the concentration of iodate (IO3(-)) in various dilutions of solution A and solution B. The results indicated discrepancies in concentration calculations, with one participant questioning their accuracy compared to a peer's results. The consensus is that concentration can be definitively calculated rather than guessed.

PREREQUISITES
  • Understanding of chemical reactions and stoichiometry
  • Familiarity with molarity calculations
  • Knowledge of potassium iodate and hydrogen sulfite ion properties
  • Basic laboratory techniques for measuring liquid volumes
NEXT STEPS
  • Learn how to calculate molarity and concentration in chemical solutions
  • Study the principles of reaction kinetics and rate laws
  • Explore the use of titration methods for concentration determination
  • Investigate the role of starch in redox reactions involving iodate
USEFUL FOR

Chemistry students, laboratory technicians, and educators involved in teaching reaction kinetics and concentration calculations will benefit from this discussion.

firebirds0707
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Solution A: is a dilute soultion of potassium iodate, KIO3 which is the source of iodate, IO2(1-)
Solution B: contains some starch and the other reacting species, the hydrogen sulfite ion, HSO3(1-)

1. In a small beaker obtain about 50mL of solution A (0.02 M IO3(-)) and in another small beaker obtain about 70mL of soulition B (HSO3(-))

Trial - Contents of Test tube 1 - Contents of Test Tube 2 - Time (s) - Concentraion IO3(-)

1 10.0mL A + 0mL water 10.0 mL B 6.9 (my guess 0.02)
2 9.0 mL A + 1mL water 10.0 mL B 8.5 (my guess 0.018)
3 8.0 mL A + 2mL water 10.0mL B 9.1 (my guess 0.016)

- My question is, am I getting the concentration right? I don't think I am and I am not sure how to figure it out.

My friend with the same lab results said he got:
1. 0.01
2. 0.09
3. 0.08

so basiclaly what I got divide by 2

Please help me out

thxx
 
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There is nothing to guess here - concentration can be calculated. And obviously your friend is better in these calculations :wink:
 
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