How can I determine the shape of an oldie acid molecule?

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SUMMARY

The discussion focuses on determining the dimensions of an oldie acid molecule using specific formulas and calculations. The participant successfully calculated the volume as 2.58 x 10^-5 cm³ and the density conversion to 0.89 g/cm³. They also derived the molecular mass as 282 g/mol and calculated the mass using the formula p = m/v, resulting in 2.2962 x 10^-5 g. However, they seek guidance on how to approach parts c and d of their homework, which involve finding the dimensions of the molecule and understanding its orientation in relation to water molecules.

PREREQUISITES
  • Understanding of molecular mass and density conversions
  • Familiarity with the formula for volume of a cuboid (v = lwh)
  • Knowledge of Avogadro's constant (Na = N/n)
  • Basic principles of molecular orientation in solutions
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Chemistry students, molecular biologists, and researchers interested in molecular dimensions and properties in solutions.

hexanimal
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Homework Statement
Finding dimension of molecule and avagadros constant
Relevant Equations
Na = N/n
v = lwh
I have done all of the questions apart from c and d. For a I got the answer 2.58*10^_5 cm^3
B) 3.72*10^-7 cm
But for c I don’t really know how to start. I first thought of using the formula for volume of cuboid but don’t know how that’d give the answer for the dimension.
For D, I turned the density from 890 kg m^-3 to 0.89 g cm^-3, found the molecular mass to be 282 and from my previous question used the volume v = 2.58*10^-5 to get mass = 2.2962*10^-5g from the formula p =m/v.
I’d just like to know how to do c and d, thanks for your help
 

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hexanimal said:
Homework Statement:: Finding dimension of molecule and avagadros constant
Relevant Equations:: Na = N/n
v = lwh

But for c I don’t really know how to start.
Consider one molecule. How is it oriented on the water? Where are other molecules in relation to it?
 

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