How can I determine the type of reaction and balance equations effectively?

  • Thread starter Thread starter JOL
  • Start date Start date
  • Tags Tags
    Tips
Click For Summary
SUMMARY

This discussion focuses on effectively balancing chemical equations and determining reaction types. Participants emphasize the importance of starting with the most abundant atom, using the example of octane (C8H18) reacting with oxygen (O2) to produce carbon monoxide (CO) and water (H2O). The conversation highlights methods such as trial-and-error and the use of linear algebra, while also addressing the need for clarity on product types, such as distinguishing between CO and CO2. Additionally, a systematic approach using tables to track atom counts before and after reactions is recommended.

PREREQUISITES
  • Basic understanding of chemical reactions and stoichiometry
  • Familiarity with balancing chemical equations
  • Knowledge of linear algebra concepts for advanced balancing techniques
  • Awareness of different types of chemical reactions (e.g., combustion, redox)
NEXT STEPS
  • Research methods for balancing chemical equations using the algebraic method
  • Study the characteristics of combustion reactions and their products
  • Learn about the principles of stoichiometry in chemical reactions
  • Explore common types of chemical reactions and their expected products
USEFUL FOR

Chemistry students, educators, and anyone involved in chemical analysis or reaction balancing will benefit from this discussion.

JOL
Messages
12
Reaction score
0
I have a problem in balancing the equation can anyone give some tips in balancing them.
 
Physics news on Phys.org


You can use some tools of linear algebra to balance them, but its not really necessary. Most equations can be balanced by trial-and-error.

If you give us a specific example, somebody will be more likely to help.
 


One of the example is:

C8H18 + O2 ----> CO + H2O
 


JOL said:
One of the example is:

C8H18 + O2 ----> CO + H2O

Notice there are three different atoms to balance. Start with anyone you like. Try the carbons. Eight on the left, so you should try making 8 on the right.
C8H18 + O2 -----> 8CO + H2O.

Notice how at least, the Hydrogens now do not balance. How do you get 18 of them on the right? There could be 9 H2O's.
C8H18 + O2 ------> 8CO + 9H2O.

Do the atoms on each side balance yet? The Oxygens do not balance yet. You find 17 Oxygens on right, but only 2 Oxygens on left. How can you represent 17 Oxygens on the left? ... Can you continue from there?

One question I have is, did you really mean "CO", or did you mean, "CO2"? This will make a bit of difference.
 
Last edited:


Thanks for the advice on balancing the reactions and I have got them to do.But another problem on my head is to solve the equation,that is the reactants are given and the products are to be written.

Need some advice.
 


JOL said:
Thanks for the advice on balancing the reactions and I have got them to do.But another problem on my head is to solve the equation,that is the reactants are given and the products are to be written.

Need some advice.

What are you asking? Are you asking which products occur if certain reactants are put into mix or solution? Are you asking to find how much of a product occurs if certain reactants are put into mix or solution?
 


My query is the former one.
 


Make a table in your notebook next to the formula with one before-reaction-coloumn and one after-reaction-coulomn. Write down how many atoms you have of each element in each coloumn, and it get's a lot easier.
 
  • #10


JOL said:
Thanks for the advice on balancing the reactions and I have got them to do.But another problem on my head is to solve the equation,that is the reactants are given and the products are to be written.

Need some advice.

Some knowledge of reactions is necessary. Decide based on qualities of the reactants and typical interrelationships which kind of reaction might be expected. Would you expect particular reactants to go through ionic rearrangement, combustion/burning, reduction-oxidation, neutralization(as for acids and bases)?
 

Similar threads

Replies
7
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 18 ·
Replies
18
Views
5K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
8
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K