How can I find the focal length of a lens silvered at one face?

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SUMMARY

The focal length of a lens silvered at one face can be determined by treating it as an effective concave lens. The effective power of the system is calculated using the formula P = P(L) + P(M) + P(L), where P(L) represents the power of the lens and P(M) represents the power of the mirror. This approach is valid because the powers of the lens and mirror combine in a manner similar to that of two lenses placed close together, allowing for a straightforward calculation of the effective focal length.

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  • Understanding of lens and mirror optics
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  • Knowledge of optical power calculations
  • Basic grasp of the lens formula (1/v - 1/u)
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Students of optics, physics educators, and anyone involved in optical design or lens system analysis will benefit from this discussion.

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Homework Statement


Its not a specific question but a general one to solve similar questions. I need to find focal length of a lens silvered at one face


Homework Equations





The Attempt at a Solution


I know a convex lens silvered at one face will behave as an effective concave lens. But i need to find the equations. I can do it by individually solving each case but need a faster one.
My book says that the effective power, P = P(L) + P(M) +P(L)...P(L) is power of lens P(M) is power of mirror. I don't know why this works?

For two lenses kept close i understand why P = P1 + P2 but don't how this works in lens-mirror case too.
Any Help?
 
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Actually it does. Just do it logically. I think that powers add because of formula being 1/v -1/u , so when you add p2 the image of 1 is oblect for 2 so basically it cancels out .p1 +p2 is just using the lens formula ignorantly . Ensure that proper sing and conditions are followed.Hope that helps
 

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