How Can I Find the Initial Velocity of a Ball Based on Angle and Window Height?

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Homework Help Overview

The problem involves determining the initial velocity of a ball kicked at an angle of 30° that reaches a window height of 9.8 m. The context is within the subject area of projectile motion.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to use equations of motion to relate the initial velocity, angle, and height but expresses uncertainty about how to proceed without knowing the horizontal distance.

Discussion Status

Some participants question the interpretation of the height as the maximum height of the trajectory, leading to different perspectives on how to approach the problem. There is no explicit consensus, but the discussion is exploring various interpretations of the problem setup.

Contextual Notes

Participants are considering the implications of the height being the maximum point in the trajectory and the potential need for additional information, such as horizontal distance, to solve the problem fully.

Kernul
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Homework Statement


A boy kicks a ball with an initial velocity v0 that forms an angle of 30° with the x. The ball, at the culmination of the trajectory, enters a window at a height of 9.8 m. Find the module of the initial velocity and the time used by the ball to reach the window. Also find the range from the initial position of the ball to the window.

Homework Equations


How do I find the initial velocity knowing just the angle and the height of the window?

The Attempt at a Solution


I tried with this equations but I still don't know how to proceed:
x = v0 * cos 30° * t
y = v0 * sin 30° * t - 1/2 * g * t2
because even if I try something like this:
t = x / v0 * cos 30°
and then I change with this in the second equation there is still the fact that I do not know the value of x.
 
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I believe by "culmination of the trajectory" it means that 9.8 m is the maximum height it can reach,which makes the problem quite easy if that's the case.
 
Oh! So I have to think of it as the maximum height!
Okay, thank you!
 
I don't have any more reason to think so than you do,though.
 

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