How can I normalize a plot by the cross-section in particle physics?

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SUMMARY

The discussion centers on normalizing a plot by the cross-section in particle physics. The correct approach is to divide the histogram by the luminosity (L) rather than the product of luminosity and cross-section (sigma*L). This is based on the relationship N = sigma*L, where N represents the number of events. Normalizing by L ensures that the total area under the curve corresponds to the total cross-section.

PREREQUISITES
  • Understanding of particle physics concepts such as cross-section and luminosity.
  • Familiarity with histogram data representation in physics.
  • Basic knowledge of scaling and normalization techniques.
  • Experience with data analysis tools used in particle physics.
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  • Research the relationship between cross-section and luminosity in particle physics.
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This discussion is beneficial for particle physicists, data analysts in experimental physics, and researchers involved in analyzing scattering events and their corresponding cross-sections.

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Just a quick question--long story short, I need to normalise a plot by the cross-section, but I'm not sure how to do that and the Google hasn't been too helpful.
I was thinking about scaling it by the cross-section times the luminosity--does this sound reasonable?
 
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Just so I have this straight -- you have a histogram in some parameter x (where x is some scattering angle or energy or something), so that the total area under the curve is the total number of events. You would like the total area under the curve to be the (total) cross-section. Is that right?

In that case, you would just divide by the luminosity, not the luminosity times the cross section. The reason is that, assuming perfect efficiency and so on, we have,

N = sigma*L

where N is the number of events, sigma is the cross-section, and L is the luminosity. Scaling the curve by sigma*L would therefore scale it by N, which would normalize your histogram to unity. If instead you want to normalize it to sigma, just divide by L.

I hope that makes sense and is what you are looking for.
 

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