How can I obtain real lengths for 'r' in the equation of a circle when R > A?

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The discussion centers on the equation of a circle in polar coordinates, specifically r = Rcos(theta) + sqrt(A^2 - (Rsin(theta))^2, where R represents the distance from the origin to the center of the circle and A is the radius. Users encounter complex values for 'r' when R exceeds A, indicating that the angle theta must be constrained to ensure real solutions. The issue arises from the geometric relationship between the radial line and the circle, which can lead to no intersection if theta is too large. A referenced resource provides visual aids and further explanations on this topic.

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Right now, I need to use the equation of a circle to describe a geometry I'm dealing with in a research project. For some reason, I cannot make sense of it, and it is extremely frustrating... Right now I'm using:

r = Rcos(theta)+sqrt(A^2-(Rsin(theta))^2)

where R is the distance from the origin to the center of the circle and A is the radius of the circle. Assume the center of the circle lies on the polar axis. I keep getting complex lengths for 'r', which obviously comes from the negative term in the square root. Can someone explain to me in a physical sense why this is happening? And my main question is how can I make it so I only obtain proper, real lengths for 'r'? Any help is appreciated
 
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What do r and theta represent? We can't tell you why your equation is giving you non-nonsensical answers if we don't know what it is, in principle, supposed to mean. Where did your equation come from?
 
In short, you are dealing with the case where R > A. In this case, value of [tex]\theta[/tex] cannot be arbitrary. If the value of [tex]\theta[/tex] is too large, there will be no intersection between the radial line and the circle.

Please refer to this http://www.voofie.com/content/78/why-do-i-get-imaginary-value-for-radius-from-equation-of-circle-in-polar-coordinate/" , which has nice graphs and detailed steps to illustrate the situation.
 
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