How can I prove that the infinite union of certain closed sets is not closed?

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Discussion Overview

The discussion revolves around the properties of infinite unions of closed sets in the context of real analysis. Participants explore specific examples of closed sets, such as \(A_n = [-\frac{1}{n}, \frac{1}{n}]\) and \(B_n = [-1+\frac{1}{n}, 1-\frac{1}{n}]\), and examine whether their infinite unions are closed or not.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant suggests that the union of sets \(A_n = [-\frac{1}{n}, \frac{1}{n}]\) is not closed because the limit point \(x=0\) is not included in any of the sets.
  • Another participant corrects the first by stating that the union of \(A_n\) is actually closed, as it equals \([-1, 1]\).
  • The same participant claims that the union of \(B_n = [-1+\frac{1}{n}, 1-\frac{1}{n}]\) results in an open set \((-1, 1)\), which is not closed.
  • A later reply asks how to prove that the union of \(B_n\) approaches \((-1, 1)\) as \(n\) tends to infinity, assuming the participant can show that points within this interval are included in the union while the endpoints are not.

Areas of Agreement / Disagreement

Participants express differing views on the closure properties of the unions of the sets discussed. There is no consensus on the closure of the union of \(A_n\), while there is agreement that the union of \(B_n\) is open.

Contextual Notes

Some participants express confusion over notation and the implications of limit points in the context of closed sets. The discussion includes assumptions about the ability to demonstrate certain properties of the sets without resolving the underlying mathematical steps.

OhMyMarkov
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Hello everyone!

I'm trying to find a set a closed set ${A_n}$ whose inifinte union is not closed. Now, I can picture the following:

If I let $A_n=[-\frac{1}{n}, \frac{1}{n}]$, then $A_n$ is closed, but their union is not, simply because the point $x=0$ seems to be a limit point at """""infinity"""", but it is not in any of the $\{A_n\}$, so the union is therefore not closed.

Now, of course, I'm having trouble showing that, because, I can't always find an $r>0$ s.t. the neighborhood of center $0$ and radius $r$ intersects any of the $\{A_n\}$s.

Similarly, I'm having trouble proving that, if $B_n = [-1+\frac{1}{n}, 1-\frac{1}{n}]$, then their infinite union is not closed.
I would appreciate any help in this... :)
 
Last edited:
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OhMyMarkov said:
Hello everyone!
I'm trying to find a set a closed set ${A_n}$ whose inifinte union is not closed. Now, I can picture the following:
If I let $A_n=[-\frac{1}{n}, \frac{1}{n}]$, then $A_n$ is closed, but their union is not, simply because the point $x=0$ seems to be a limit point at """""infinity"""", but it is not in any of the $\{A_n\}$, so the union is therefore not closed.

Now, of course, I'm having trouble showing that, because, I can't always find an $r>0$ s.t. the neighborhood of center $0$ and radius $r$ intersects any of the $\{A_n\}$s.

Similarly, I'm having trouble proving that, if $B_n = [-1+\frac{1}{n}, 1-\frac{1}{n}]$, then their infinite union is not closed.
You are confused on notation.
$\bigcup\limits_n {\left[ { - \frac{1}{n},\frac{1}{n}} \right]} = \left[ { - 1,1} \right]$ which is a closed set.

$\bigcup\limits_n {\left[ { - 1 + \frac{1}{n},1 - \frac{1}{n}} \right]} = \left( { - 1,1} \right)$ which is an open set.
Note that $\left( { - 1 + \frac{1}{n}} \right) \to - 1$ is a decreasing sequence.
Note that $\left( {1 - \frac{1}{n}} \right) \to 1$ is an increasing sequence.
What is your question?
 
Hi Plato!

Thanks for your reply.

My question is, how can I prove that the union of $[-1+\frac{1}{n}, 1-\frac{1}{n}]$ tends to $(-1,1)$ as $n$ tends to infinity?
 
OhMyMarkov said:
Hi Plato!

Thanks for your reply.

My question is, how can I prove that the union of $[-1+\frac{1}{n}, 1-\frac{1}{n}]$ tends to $(-1,1)$ as $n$ tends to infinity?

I will assume that you have no trouble showing that \(x \in (-1,1)\) is in at least one of the sets: \([-1+\frac{1}{n}, 1-\frac{1}{n}],\ \ n \in \mathbb{N}_+\) and hence in their union . Also that you have no trouble showing that \(\pm 1\) are in none of \([-1+\frac{1}{n}, 1-\frac{1}{n}], \ \ n\in \mathbb{N}_+\) and hence not in their union.

(I am also assuming you have no problem for x >1 or x<-1 either)

Then you are done.

CB
 
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