How Can I Prove the Reciprocal Derivative Identity?

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SUMMARY

The reciprocal derivative identity, expressed as \(\frac{dy}{dx}\frac{dx}{dy} = 1\), can be proven using the chain rule in calculus. When \(y = f(x)\) and \(f\) is an invertible function, differentiating both sides of the equation \(f^{-1}(f(x)) = x\) with respect to \(x\) leads to the conclusion that \(\frac{dx}{dy}\frac{dy}{dx} = 1\). This establishes the identity definitively, confirming its validity through the properties of inverse functions.

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  • Familiarity with the chain rule in differentiation
  • Knowledge of inverse functions and their properties
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danago
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Hi. I was just wondering, how can i prove the following identity:

[tex] \frac{{dy}}{{dx}}\frac{{dx}}{{dy}} = 1[/tex]

Its nothing that I am required to know, but i was just curious, so for all i know, it may be way out of anything that i can mathematically comprehend.

The best I've been able to do is show that it holds true for some examples that I've tried, but no solid proof.

Thanks in adavnce,
Dan.
 
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It should be easy using the chain rule. If y= f(x) and f is invertible, then
x= f-1(y), so that f-1(f(x))= x. Differentiating both sides of that with respect to x,
[tex]\frac{df^{-1}(y)}{dy}\frac{dy}{dx}= 1[/itex]<br /> Where I have 'let' y= f(x). Since f<sup>-1</sup>(y)= x, that is <br /> [tex]\frac{dx}{dy}\frac{dy}{dx}= 1[/itex][/tex][/tex]
 
Ah, easy. Thanks very much for that :smile:
 

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