How Can I Prove Vector Identities Using Algebraic Manipulation?

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SUMMARY

The discussion focuses on proving vector identities using algebraic manipulation, specifically the equations |u x v|^2 = (u . u)(v . v) - (u . v)^2 and u . (v x w) = 0. Participants emphasize the importance of understanding the magnitude of the cross product and its relationship with the sine of the angle between vectors. A suggestion is made to utilize trigonometric identities to simplify the proof process. The initial confusion regarding vector representation is addressed, leading to a clearer path for solving the problems.

PREREQUISITES
  • Understanding of vector operations, including dot and cross products
  • Familiarity with trigonometric identities, particularly sine and cosine
  • Basic knowledge of vector representation in three-dimensional space
  • Ability to manipulate algebraic expressions involving vectors
NEXT STEPS
  • Study the properties of the cross product and its geometric interpretation
  • Learn about trigonometric identities and their applications in vector mathematics
  • Explore vector algebra techniques for simplifying expressions
  • Practice solving vector identity proofs using various methods
USEFUL FOR

Students studying vector calculus, mathematics enthusiasts, and anyone looking to enhance their understanding of vector identities and algebraic manipulation techniques.

doggbAT
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Homework Statement


Question One: Prove that |u x v|^2 = (u . u)(v . v)-(u . v)^2 where u and v are vectors.

Question Two: Given that u = sv + tw, prove algebraically that u . v x w = 0 where u, v and w are vectors and s and t are integers.

Homework Equations


I don't know :(

The Attempt at a Solution


I have expanded the equations, expressing vectors as [x,y,z].. I have no direction after that. I am curious how you would explain that the cross product of two vectors = 0 without the vectors having any value. Any help is greatly appreciated.
 
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doggbAT said:

Homework Statement


Question One: Prove that |u x v|^2 = (u . u)(v . v)-(u . v)^2 where u and v are vectors.

Question Two: Given that u = sv + tw, prove algebraically that u . v x w = 0 where u, v and w are vectors and s and t are integers.

Homework Equations


I don't know :(

The Attempt at a Solution


I have expanded the equations, expressing vectors as [x,y,z].. I have no direction after that. I am curious how you would explain that the cross product of two vectors = 0 without the vectors having any value. Any help is greatly appreciated.

I think that expressing your vectors in terms of x, y, and z is the wrong way to go about it. Try recalling the definition of the magnitude of the cross product as the magnitude of each of the vectors times the sine of the angle between them. (Note that you're squaring the magnitude of the cross product.) Now u dot u is just u squared, etc and what is another way to write sine squared? (Hint: it uses a familiar trig identity). This should get you started.
 
Thank you :D I've answered the first question, and am now working on the second question. Your help worked perfectly!
 

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