How can I simplify a nested square roots limit without using l'Hopital's rule?

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SUMMARY

The discussion focuses on simplifying the limit of a nested square root function without using l'Hôpital's rule. Participants suggest rewriting the expression, specifically sqrt(x + sqrt(x)), as sqrt(x) * sqrt(1 + 1/sqrt(x)) to facilitate the limit evaluation. They emphasize the importance of factoring out sqrt(x) from both the numerator and denominator to avoid complications associated with l'Hôpital's rule. The consensus is that the limit approaches 1 as x approaches infinity.

PREREQUISITES
  • Understanding of limits in calculus
  • Familiarity with square root properties
  • Basic knowledge of algebraic manipulation
  • Concept of indeterminate forms
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  • Study techniques for simplifying limits involving square roots
  • Learn about indeterminate forms and their resolutions
  • Explore alternative methods to l'Hôpital's rule for limit evaluation
  • Practice problems involving nested functions in calculus
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Students studying calculus, particularly those tackling limits and nested functions, as well as educators seeking effective teaching strategies for limit simplification.

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Homework Statement


lim2.jpg



Homework Equations





The Attempt at a Solution



I don't have any idea to simplify the function please help me...
 
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It's more awkward to write than hard.
sqrt(x+sqrt(x))=sqrt(x)*sqrt(1+1/sqrt(x)). Now pull a sqrt(x) out of the outer sqrt so you've got sqrt(x+sqrt(x+sqrt(x)))=sqrt(x)*(1+(1/sqrt(x))*sqrt(1+1/sqrt(x))). The denominator is sqrt(x)*sqrt(1+1/x). Now cancel the sqrt(x) on the outside and take the limit. If you can read that I congratulate you. I THINK I got it right.
 


The answer is 1... but how did you came up with the equivalent equation for the numerator? :(
 


It's probably advisable not to use L'hospital because of the nested square roots. Instead, follow what Dick said (I'm hoping I did it the same way he did because I didn't read his post in detail) and start by pulling out all the square roots by making sure that the denominator and numerator share the same square root over the entire expresion.

Then apply that technique inside the nested root. It'll all simplify to something which you can evaluate the limit to.
 


Defennder said:
It's probably advisable not to use L'hospital because of the nested square roots. Instead, follow what Dick said (I'm hoping I did it the same way he did because I didn't read his post in detail) and start by pulling out all the square roots by making sure that the denominator and numerator share the same square root over the entire expresion.

Then apply that technique inside the nested root. It'll all simplify to something which you can evaluate the limit to.

Right. l'Hopital gets messy. But you can write both numerator and denominator as sqrt(x) times something that goes to 1 as x->infinity. Just factor them both as sqrt(x)*something.
 


l'Hopital gets messy indeed. But, hey, at least it's honest. :-p
 


Timmo said:
l'Hopital gets messy indeed. But, hey, at least it's honest. :-p

So is factoring out the dominant term.
 

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