- #1
Rnotaria
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Limit √(4x^(2)+x) -2x
x→∞
(Should read like: Square root of (4x squared plus x) minus 2x
I know you have to use L'Hopital's rule and I multiplied it by the conjugate to get a denominator, but every time I apply the rule it just goes on an infinite loop. Does anyone know how to solve this please?
Answer is 1/4
x→∞
(Should read like: Square root of (4x squared plus x) minus 2x
I know you have to use L'Hopital's rule and I multiplied it by the conjugate to get a denominator, but every time I apply the rule it just goes on an infinite loop. Does anyone know how to solve this please?
Answer is 1/4
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