How Can I Simplify This Complex Mathematical Expression?

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Discussion Overview

The discussion revolves around simplifying a complex mathematical expression involving variables z and w, with a specific value for w provided. Participants explore different methods of simplification and seek clarity on the expression's formulation.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant presents a mathematical expression to simplify, expressing a desire to learn multiple methods for understanding.
  • Another participant questions whether the original expression was correctly transcribed, suggesting a possible correction from x to z.
  • A participant provides a step-by-step simplification of the expression, ultimately arriving at a numerical result for w=2.
  • There is a light-hearted comment about the ability to solve the expression despite potential transcription errors.

Areas of Agreement / Disagreement

Participants generally agree on the expression's simplification process, but there is uncertainty regarding the initial formulation of the expression itself.

Contextual Notes

There may be missing assumptions regarding the interpretation of variables and potential transcription errors that could affect the simplification process.

headbang
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Hello,
I am having difficulty solving my math problems.

Simplify the Expression and show how.. And kalkulate

z²+w(2wz)²-(w+4z²-1)w³-(z+w²)(x-w²)

And w=2

I know we have many ways doing it, an the more ways i can study, the bether i can understand this..
 
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headbang said:
Hello,
I am having difficulty solving my math problems.

Simplify the Expression and show how.. And kalkulate

z²+w(2wz)²-(w+4z²-1)w³-(z+w²)(x-w²)

And w=2

I know we have many ways doing it, an the more ways i can study, the bether i can understand this..

Do you maybe mean:

$z^2+w(2wz)^2-(w+4z^2-1)w^3-(z+w^2)($z$-w^2)$

($z$ instead of $x$) ?? (Wondering)

If so, it is as followed:

$$z^2+w(2wz)^2-(w+4z^2-1)w^3-(z+w^2)(z-w^2) \\ =z^2+w 4 w^2 z^2-ww^3-4z^2w^3+w^3-(z^2-zw^2+zw^2-w^4) \\ =z^2+4 w^3 z^2-w^4-4z^2w^3+w^3-(z^2-w^4) \\ =z^2-w^4+w^3-z^2+w^4=w^3$$

For $w=2$ we have

$$2^3=8$$
 
You are so good.. You solved it even if i can't read and Write the right Expression... :)
 
headbang said:
You are so good.. You solved it even if i can't read and Write the right Expression... :)
I suspect that MHB is conducting secret genetic experimentation on some members to promote psychic abilities.

-Dan
 

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