You can solve each equation individually for tau. Then, since the results must be equal, you can equate them. This will give you a relationship between V1, t1, and V2, t2.
Example of solving one of the equations:
[tex]V_1 = V_f (1 - e^{-t_1 / \tau} )[/tex]
Divide both sides by V
f:
[tex]\frac{V_1}{V_f} = 1 - e^{-t_1 / \tau}[/tex]
Subtract V
1 / V
f from both sides. Then add the exponential term to both sides (in other words, rearrange the terms):
[tex]e^{-t_1 / \tau} = 1 - \frac{V_1}{V_f}[/tex]
Take the natural logarithm of both sides of the equation:
[tex]-\frac{t_1}{\tau} = \ln \left[1 - \frac{V_1}{V_f} \right][/tex]
Solve for tau by multiplying both sides by tau and then dividing both sides by the ln term (in other words, cross-multiply):
[tex]\tau = -\frac{t_1}{\ln \left[1 - \frac{V_1}{V_f} \right]}[/tex]
Now, when you solve the second equation for tau, you'll get a similar answer in terms of V
2 and t
2. Since it must be true that tau = tau, you can equate these results.