How can I solve inequalities involving absolute values?

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Homework Help Overview

The discussion revolves around proving inequalities involving absolute values, specifically the triangle inequality and its implications for two given statements. Participants are exploring the mathematical properties and relationships of absolute values in the context of inequalities.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss attempts to prove the inequalities by leveraging the triangle inequality. One participant questions the validity of their approach involving squaring the expressions, while others suggest using substitutions to simplify the proofs.

Discussion Status

Some participants have made progress on the first inequality and are seeking further clarification on the second. There is an acknowledgment of the interconnectedness of the problems, and guidance has been offered regarding the use of the triangle inequality.

Contextual Notes

Participants note that the problems are part of a larger context in a textbook, which may require using earlier results to solve later parts. There is a mention of the potential difficulty of the problems and the possibility of needing to assume earlier results for later proofs.

carlosbgois
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Homework Statement



d) Show that [itex]\left|x-y\right| \leq \left|x\right|+\left|y\right|[/itex]
e) Show that [itex]\left|x\right|-\left|y\right| \leq \left|x-y\right|[/itex]

The Attempt at a Solution



For item d) I've tried some approaches but none was promising.

For item e), I tried squaring [itex]\left|x-y\right|[/itex] to get
[itex](\left|x-y\right|)^{2} \geq (\left|x\right|-\left|y\right|)^{2}[/itex]

But if I take the square roots, the right side may not always be positive, then I don't have a proof, right?

Thanks
 
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carlosbgois said:

Homework Statement



d) Show that [itex]\left|x-y\right| \leq \left|x\right|+\left|y\right|[/itex]
e) Show that [itex]\left|x\right|-\left|y\right| \leq \left|x-y\right|[/itex]

The Attempt at a Solution



For item d) I've tried some approaches but none was promising.

For item e), I tried squaring [itex]\left|x-y\right|[/itex] to get
[itex](\left|x-y\right|)^{2} \geq (\left|x\right|-\left|y\right|)^{2}[/itex]

But if I take the square roots, the right side may not always be positive, then I don't have a proof, right?

Thanks

Do you have the ordinary triangle inequality to work with: |x+y| ≤ |x| + |y|? You can get these by using it. For example, what happens if you substitute -y for y in that?
 
Yes I do, and I got the answer with your help:

Having the triangular inequality and substituting y for -y, we get:
[itex]|x+(-y)|\leq|x|+|-y|[/itex]. As [itex]|y|=|-y|[/itex], then [itex]|x-y|\leq|x|+|y|[/itex].

But what about the second exercise? I now was able to do it using the first one,
but is there any way of getting it right with my previous attempt, which I posted up there?

Thanks
 
carlosbgois said:
But what about the second exercise? I now was able to do it using the first one,
but is there any way of getting it right with my previous attempt, which I posted up there?

Thanks

This will be a common trend throughout Spivak. Many of the questions have multiple parts and the later parts often require the earlier parts to complete the proof; although, I think this occurs more frequently when you get to the real meat of the book beginning in chapter 9. It's common for previous, perhaps long forgotten, problems to be used in the proofs as well. Also Spivak has a lot of difficult problems so you might come to a point later in the book where you need to skip part A and just assume its true to solve part B - at least I occasionally did :)
 

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