How can I understand the Thevenin Theorem and its formula for e?

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Homework Help Overview

The discussion revolves around understanding the Thevenin Theorem and the specific formula for voltage (e) in a circuit context. Participants are exploring the derivation and application of this theorem, particularly in relation to voltage dividers and circuit analysis.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are attempting to clarify the derivation of the formula e = V1R3/(R1 + R3) and its application in circuit analysis. Questions are raised about the role of current through resistors and the implications of open circuit conditions.

Discussion Status

The discussion is ongoing, with some participants providing insights into Kirchhoff's rules and voltage divider concepts. There is a mix of understanding and confusion, with participants sharing resources to aid comprehension. No explicit consensus has been reached yet.

Contextual Notes

Some participants express uncertainty about foundational concepts like voltage dividers and circuit analysis, indicating a potential gap in knowledge that may affect their understanding of the Thevenin Theorem.

thelovemonkey
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Homework Statement



hey guys. I am new to the board. I've seen this problem on a website of which i'll list below. I am not sure how came up with that formula for e.


http://hyperphysics.phy-astr.gsu.edu/HBASE/electric/thevenin.html -> is the link to the page.

i understand the rest of the problem, thaz the only thing thaz giving me a hard time. thanks in advance for ur helps. cheers.
 
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Welcome to PF!

thelovemonkey said:
ive seen this problem on a website of which i'll list below. I am not sure how came up with that formula for e.

Hi thelovemonkey! Welcome to PF! :wink:

Do you mean e = V1R3/(R1 + R3) ?

Since no current is flowing through R2, the voltage across AB is the same as the voltage across R3, which you can calculate from Kirchhoff's rules :smile:
 
oh okay okay i udnerstand that. but i don't quite understand the actual equation e = V1R3/(R1 + R3) as in how it was derived.
 
When nodes a and b are open, no current will flow through R2. Since there is no current through R2, there will be no voltage drop across R2. So therefore, the open circuit voltage is simply the voltage across R3. Which if you do KVL, or just a simple voltage divider equation, you'll get to the equation that's in question.What does your Kirchoff equation look like?
 
Last edited:
aw man. i think that's my problem right there. i don't know about voltage divider equatiosn and stuff.
 
Ok, try to sum up the current at the point between R1 and R3. We know from the link that tiny-kim gave us, that this summation will equal zero. Even more helpful is the formula V=I*R. , so we'll get something like ( V_oc / R3 ) as the current through the resistor R3. V_oc means Voltage of open circuit. Now what will the current be for R1? What is the voltage difference between the source voltage and V_oc? Then from there, what's the current knowing the resistance is R1? Is this current the same current as that flowing through R3? Why? Once you get an equation in terms of voltages and resistances, then it becomes some algebraic maneuvering to achieve the desired formula.

There's a a few details in dealing with whether or not the current's sign should be positive or negative, which can be addressed using the passive sign convention.

http://en.wikiversity.org/wiki/Passive_sign_convention There's a good link for you to look at and digest.
 
hurray for b00bies i found it. this link helped sort the voltage divider thing for me
http://www.allaboutcircuits.com/vol_1/chpt_6/1.html

sorry guys no offence or anything. but i haven't understood quite clearly from the way you've explained. however. ur links and stuff were good reads and helped me out in other aspects of electricity.

im doing first year civil engineering and gotto do a semester of electronics.



BTW. anyone of u guys have an eFormula sheet for electronics?
 

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