How can the rationalized numerator be simplified?

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Homework Help Overview

The discussion revolves around simplifying the expression \(\frac {\sqrt{2x+3}+1}4\) and understanding the rationalization process involved. Participants are examining the steps taken to reach a simplified form and the discrepancies noted in the expected results.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the rationalization of the numerator and the steps taken to simplify the expression. Questions arise regarding the correctness of the final form provided by a figure named Doc Lang, with some participants expressing confusion over the presence of parentheses in the denominator.

Discussion Status

The discussion has seen participants confirming each other's calculations, but there remains uncertainty regarding the interpretation of the denominator. While some participants suggest that no further discussion is needed, the exact reasoning behind the expected result is still questioned.

Contextual Notes

There is mention of potential miscommunication regarding the formatting of the denominator in the expected answer, which may affect the interpretation of the simplification process.

r0bHadz
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Homework Statement


\frac {\sqrt{2x+3}+1}4

Homework Equations

The Attempt at a Solution


\frac {\sqrt{2x+3}+1}4 * \frac {\sqrt{2x+3}-1}{\sqrt{2x+3}-1} = \frac {2x+3-1}{4\sqrt{2x+3}-4} = \frac {2x+2}{4\sqrt{2x+3}-4} = \frac {2(x+1)}{2(2\sqrt{2x+3}-2)} = \frac {x+1}{2\sqrt{2x+3} -2}

but doc. Lang is telling me the answer is \frac {x+1}{2(\sqrt{2x+3}-2)}

How did he come to this result??
 
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r0bHadz said:

Homework Statement


\frac {\sqrt{2x+3}+1}4

Homework Equations

The Attempt at a Solution


\frac {\sqrt{2x+3}+1}4 * \frac {\sqrt{2x+3}-1}{\sqrt{2x+3}-1} = \frac {2x+3-1}{4\sqrt{2x+3}-4} = \frac {2x+2}{4\sqrt{2x+3}-4} = \frac {2(x+1)}{2(2\sqrt{2x+3}-2)} = \frac {x+1}{2\sqrt{2x+3} -2}

but doc. Lang is telling me the answer is \frac {x+1}{2(\sqrt{2x+3}-2)}

How did he come to this result??
Yes, you are correct.
 
SammyS said:
Yes, you are correct.

Thank you no more discussion is needed. I'm going to assume Lang didn't intend for there to be "(" after the first two in the denominator
 
r0bHadz said:
Thank you no more discussion is needed. I'm going to assume Lang didn't intend for there to be "(" after the first two in the denominator
... or he intended the denominator to be: ##\ 2(\sqrt{2x+3\,} -1)\,. ##
 
SammyS said:
... or he intended the denominator to be: ##\ 2(\sqrt{2x+3\,} -1)\,. ##
True that.
 

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