How can torque be used to solve for tension in an extended free body diagram?

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SUMMARY

This discussion focuses on using torque to solve for tension in an extended free body diagram, specifically in the context of a physics homework problem. The key equations involved are T = Iα for torque and the equilibrium equations for the x and y components. The solution requires three equations to solve for the three unknowns, with the torque equation being essential. The moment of a force is defined as the product of the force and the perpendicular distance from the point of rotation, which simplifies the analysis of tension in the system.

PREREQUISITES
  • Understanding of torque and its relation to rotational motion
  • Familiarity with free body diagrams and equilibrium conditions
  • Knowledge of trigonometric functions in resolving forces
  • Basic grasp of Newton's laws of motion
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  • Study the concept of torque and its application in rotational dynamics
  • Learn how to create and analyze extended free body diagrams
  • Explore the relationship between tension and torque in mechanical systems
  • Practice solving problems involving multiple unknowns using equilibrium equations
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Students studying physics, particularly those focusing on mechanics, as well as educators looking for detailed explanations on applying torque in problem-solving scenarios.

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Homework Statement


I need help with this: http://img716.imageshack.us/img716/3262/unledewk.jpg

I know that I need to create an extended free body diagram and I understand how to get all the equations from the diagram. BUT I don't know what to do when it comes time to use torque and find tension


Homework Equations


T = Ialpha


The Attempt at a Solution


x-component : N - Tcos(35) = 0
y-component : Tsin(35) + U - 2.5g = 0

I get stuck at this point and don't know how to use torque to solve for T. I'm pretty confused with the concept of it, so if you can, please try to be a little thorough in walking me through the rest of the problem.
 
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There are 3 unknown physical quantities and so we require 3 equations if one wants to find all three unknowns.

The third equation is the torque equation as you yourself mentioned. I would take moments about the pin so that forces U and N do not enter.

Remember that moment of a force about a point is given by the product of the force and perpendicular distance of the line of action of this force from the given point.

One can simplify the moment equation if the tension is resolved into components - one along the bar and passing through the pin and the other perpendicular to the bar.
 

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