How can trigonometry be used to calculate distance in physics problems?

AI Thread Summary
To calculate the distance Bob is from the shore after heading out at a 36-degree angle for 7 minutes and 23 seconds, first convert the time to seconds, which is 443 seconds. Using the formula for distance (distance = speed × time), multiply Bob's speed of 1.7 m/s by 443 seconds to find the total distance traveled. The resulting distance is the hypotenuse of a right triangle, where the angle can be used with trigonometric functions to find the perpendicular distance from the shore. Specifically, the sine function can be applied to determine how far Bob is from the shore based on the angle and hypotenuse. This approach effectively utilizes trigonometry to solve the physics problem.
fireykitty
Messages
5
Reaction score
0

Homework Statement



Bob heads out into a lake at an angle of 36 degrees, with respect to the shore. If his boat is capable of a speed of 1.7 m/s, how far from land will he be in 7 min and 23 s? Answer in units of m.


Homework Equations



I have no idea what equation would work for this. It was about to apply projectile motion but "g" does not apply to this, and equations for projectile motion involve "g" ...

The Attempt at a Solution



All I've figured out in the past two hours is that 7 min and 23 s = 443 seconds.


Hints/Equations/Anything?
 
Physics news on Phys.org
How many meters is that?

Now that you have distance, don't you have a hypotenuse?

If you have the angle, then what trig function times the hypotenuse will yield your distance perpendicular from the shore?
 
LowlyPion said:
How many meters is that?

Now that you have distance, don't you have a hypotenuse?

If you have the angle, then what trig function times the hypotenuse will yield your distance perpendicular from the shore?



How many meters is what?

I don't have a distance.

I was thinking inverse cos of 36 degrees. That would give me the hypotenuse right?
 
fireykitty said:
How many meters is what?

I don't have a distance.

You have the time. You have the velocity.

Why don't you have the distance traveled?
 
This is a trig problem. Make a diagram, the boat leaves the shore at an angle. Distance traveled equals rate X time, you have both as pointed out by Lowlypion. Use the appropriate trig function to solve for the distance the boat is from the shore after 443 seconds.
 
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Struggling to make relation between elastic force and height'
Hello guys this is what I tried so far. I used the UTS to calculate the force it needs when the rope tears. My idea was to make a relationship/ function that would give me the force depending on height. Yeah i couldnt find a way to solve it. I also thought about how I could use hooks law (how it was given to me in my script) with the thought of instead of having two part of a rope id have one singular rope from the middle to the top where I could find the difference in height. But the...
Back
Top