How can trigonometry be used to calculate distance in physics problems?

Click For Summary

Homework Help Overview

The problem involves calculating the distance a boat travels from the shore while moving at an angle of 36 degrees. The boat's speed is given, and the time of travel is specified, requiring the application of trigonometric principles to determine the distance from the shore.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between time, speed, and distance, with some questioning the use of trigonometric functions to find the distance from the shore. There is mention of using the hypotenuse and the need for a diagram to visualize the problem.

Discussion Status

Participants are actively engaging with the problem, raising questions about the calculations and the application of trigonometry. Some guidance has been offered regarding the relationship between distance, speed, and time, as well as the use of trigonometric functions.

Contextual Notes

There is a lack of clarity regarding the initial distance from the shore and how to apply the angle in the context of the problem. Participants are also exploring the implications of the given speed and time on the overall calculation.

fireykitty
Messages
5
Reaction score
0

Homework Statement



Bob heads out into a lake at an angle of 36 degrees, with respect to the shore. If his boat is capable of a speed of 1.7 m/s, how far from land will he be in 7 min and 23 s? Answer in units of m.


Homework Equations



I have no idea what equation would work for this. It was about to apply projectile motion but "g" does not apply to this, and equations for projectile motion involve "g" ...

The Attempt at a Solution



All I've figured out in the past two hours is that 7 min and 23 s = 443 seconds.


Hints/Equations/Anything?
 
Physics news on Phys.org
How many meters is that?

Now that you have distance, don't you have a hypotenuse?

If you have the angle, then what trig function times the hypotenuse will yield your distance perpendicular from the shore?
 
LowlyPion said:
How many meters is that?

Now that you have distance, don't you have a hypotenuse?

If you have the angle, then what trig function times the hypotenuse will yield your distance perpendicular from the shore?



How many meters is what?

I don't have a distance.

I was thinking inverse cos of 36 degrees. That would give me the hypotenuse right?
 
fireykitty said:
How many meters is what?

I don't have a distance.

You have the time. You have the velocity.

Why don't you have the distance traveled?
 
This is a trig problem. Make a diagram, the boat leaves the shore at an angle. Distance traveled equals rate X time, you have both as pointed out by Lowlypion. Use the appropriate trig function to solve for the distance the boat is from the shore after 443 seconds.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
4K
Replies
15
Views
3K
Replies
4
Views
4K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 37 ·
2
Replies
37
Views
5K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 10 ·
Replies
10
Views
6K
Replies
8
Views
3K