Projectile with Air resistance problem

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SUMMARY

The discussion centers on solving a projectile motion problem with air resistance, where the resistance is proportional to speed. The terminal velocity is given as 19.6 m/s, leading to the determination of the constant k in terms of mass m, yielding k = m/2. The participants explore the equations of motion for a projectile launched upwards at an initial speed of 6 m/s, emphasizing the need to account for forces acting in opposite directions, specifically gravity and air resistance. The correct formulation of the differential equation and its solution using separation of variables is crucial for finding the velocity as a function of time.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with differential equations
  • Knowledge of terminal velocity concepts
  • Basic calculus for solving ODEs
NEXT STEPS
  • Study the derivation of terminal velocity in fluid dynamics
  • Learn about solving first-order differential equations using separation of variables
  • Explore the effects of air resistance on projectile motion
  • Investigate the relationship between forces and acceleration in various motion scenarios
USEFUL FOR

Students in physics, particularly those studying mechanics, as well as educators and anyone interested in understanding the dynamics of projectile motion with air resistance.

  • #31
Guys! I think I've got the answer, I'm just going to upload it now. PLEASE BE RIGHT! :nb)
 
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  • #32
Part a) F=mg and F=kv

Therefore mg=kv and v=19.6 (terminal velocity)
k = mg/v
k = mg/19.6

Part b)

Equation of motion -> -mg-kv = ma
(Sub in k =mg/v)
-2mg = ma
a = -2g
dv/dt = -2g
v = -2gt

Or maybe instead of subbing in k=mg/v It should have been mg/19.6?

Voila! Surely that's correct right?!
 
Last edited:
  • #33
ZenchiT said:
Part a) F=mg and F=kv

Therefore mg=kv and v=19.6 (terminal velocity)
k = mg/v
k = mg/19.6

Part b)

Equation of motion -> -mg-kv = ma
(Sub in k =mg/v)
-2mg = ma
a = -2g
dv/dt = -2g
v = -2gt

Or maybe instead of subbing in k=mg/v It should have been mg/19.6?

Voila! Surely that's correct right?!
For the value of k, as I mentioned, if you are going to put numbers representing dimensioned quantities in the answer then you also need units. You don't need units for m and g since symbolic variables encapsulate the physical quantity independently of units. So you just need the right units for the 1/19.6 factor. What would those be?
For part b), you have used the same symbol v for two different velocities, the terminal velocity and the initial velocity. So, yes, you should have substituted mg/19.6 (with units) for k.
 
  • #34
haruspex said:
For the value of k, as I mentioned, if you are going to put numbers representing dimensioned quantities in the answer then you also need units. You don't need units for m and g since symbolic variables encapsulate the physical quantity independently of units. So you just need the right units for the 1/19.6 factor. What would those be?
For part b), you have used the same symbol v for two different velocities, the terminal velocity and the initial velocity. So, yes, you should have substituted mg/19.6 (with units) for k.
Would it have N as the units because it has the same dimensions as force?
 
  • #35
ZenchiT said:
Would it have N as the units because it has the same dimensions as force?
The problem is the lack of units for the 19.6. What units should that have? So what units will the 1/19.6 have?
 
  • #36
haruspex said:
The problem is the lack of units for the 19.6. What units should that have? So what units will the 1/19.6 have?
m/s^-1 as its terminal velocity?

Thank you for the amount of help you've given me!
 
  • #37
ZenchiT said:
m/s^-1 as its terminal velocity?

Thank you for the amount of help you've given me!
m/s, or ms-1 (but not m/s-1) is right for the 19.6. So what should it be for 1/19.6?
 
  • #38
ZenchiT said:
Part a) F=mg and F=kv

Therefore mg=kv and v=19.6 (terminal velocity)
k = mg/v
k = mg/19.6

Part b)

Equation of motion -> -mg-kv = ma
(Sub in k =mg/v)
-2mg = ma
a = -2g
dv/dt = -2g
v = -2gt

Or maybe instead of subbing in k=mg/v It should have been mg/19.6?

Voila! Surely that's correct right?!
Well, surely that is incorrect! (sorry to rain on your parade). The initial velocity is given as +6 m/s and your formula says initial velocity = 0!
Your equation of motion is correct but you are not solving the ODE correctly. Hint: try separation of variables.
 

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