Projectile with Air resistance problem

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The discussion revolves around solving a projectile motion problem with air resistance, where the resistance is proportional to speed. In part (a), participants attempt to determine the constant k using the terminal velocity of 19.6 m/s, with some confusion regarding units and signs in their equations. For part (b), the focus shifts to formulating the equation of motion for a projectile launched upwards at 6 m/s, but there is significant debate about the correct application of forces and the integration process. Key misunderstandings include the direction of forces and the proper treatment of dimensions in equations. Ultimately, the conversation highlights the complexities of applying Newton's laws and calculus to motion with air resistance.
  • #31
Guys! I think I've got the answer, I'm just going to upload it now. PLEASE BE RIGHT! :nb)
 
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  • #32
Part a) F=mg and F=kv

Therefore mg=kv and v=19.6 (terminal velocity)
k = mg/v
k = mg/19.6

Part b)

Equation of motion -> -mg-kv = ma
(Sub in k =mg/v)
-2mg = ma
a = -2g
dv/dt = -2g
v = -2gt

Or maybe instead of subbing in k=mg/v It should have been mg/19.6?

Voila! Surely that's correct right?!
 
Last edited:
  • #33
ZenchiT said:
Part a) F=mg and F=kv

Therefore mg=kv and v=19.6 (terminal velocity)
k = mg/v
k = mg/19.6

Part b)

Equation of motion -> -mg-kv = ma
(Sub in k =mg/v)
-2mg = ma
a = -2g
dv/dt = -2g
v = -2gt

Or maybe instead of subbing in k=mg/v It should have been mg/19.6?

Voila! Surely that's correct right?!
For the value of k, as I mentioned, if you are going to put numbers representing dimensioned quantities in the answer then you also need units. You don't need units for m and g since symbolic variables encapsulate the physical quantity independently of units. So you just need the right units for the 1/19.6 factor. What would those be?
For part b), you have used the same symbol v for two different velocities, the terminal velocity and the initial velocity. So, yes, you should have substituted mg/19.6 (with units) for k.
 
  • #34
haruspex said:
For the value of k, as I mentioned, if you are going to put numbers representing dimensioned quantities in the answer then you also need units. You don't need units for m and g since symbolic variables encapsulate the physical quantity independently of units. So you just need the right units for the 1/19.6 factor. What would those be?
For part b), you have used the same symbol v for two different velocities, the terminal velocity and the initial velocity. So, yes, you should have substituted mg/19.6 (with units) for k.
Would it have N as the units because it has the same dimensions as force?
 
  • #35
ZenchiT said:
Would it have N as the units because it has the same dimensions as force?
The problem is the lack of units for the 19.6. What units should that have? So what units will the 1/19.6 have?
 
  • #36
haruspex said:
The problem is the lack of units for the 19.6. What units should that have? So what units will the 1/19.6 have?
m/s^-1 as its terminal velocity?

Thank you for the amount of help you've given me!
 
  • #37
ZenchiT said:
m/s^-1 as its terminal velocity?

Thank you for the amount of help you've given me!
m/s, or ms-1 (but not m/s-1) is right for the 19.6. So what should it be for 1/19.6?
 
  • #38
ZenchiT said:
Part a) F=mg and F=kv

Therefore mg=kv and v=19.6 (terminal velocity)
k = mg/v
k = mg/19.6

Part b)

Equation of motion -> -mg-kv = ma
(Sub in k =mg/v)
-2mg = ma
a = -2g
dv/dt = -2g
v = -2gt

Or maybe instead of subbing in k=mg/v It should have been mg/19.6?

Voila! Surely that's correct right?!
Well, surely that is incorrect! (sorry to rain on your parade). The initial velocity is given as +6 m/s and your formula says initial velocity = 0!
Your equation of motion is correct but you are not solving the ODE correctly. Hint: try separation of variables.
 

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