ZenchiT
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Guys! I think I've got the answer, I'm just going to upload it now. PLEASE BE RIGHT! 


For the value of k, as I mentioned, if you are going to put numbers representing dimensioned quantities in the answer then you also need units. You don't need units for m and g since symbolic variables encapsulate the physical quantity independently of units. So you just need the right units for the 1/19.6 factor. What would those be?ZenchiT said:Part a) F=mg and F=kv
Therefore mg=kv and v=19.6 (terminal velocity)
k = mg/v
k = mg/19.6
Part b)
Equation of motion -> -mg-kv = ma
(Sub in k =mg/v)
-2mg = ma
a = -2g
dv/dt = -2g
v = -2gt
Or maybe instead of subbing in k=mg/v It should have been mg/19.6?
Voila! Surely that's correct right?!
Would it have N as the units because it has the same dimensions as force?haruspex said:For the value of k, as I mentioned, if you are going to put numbers representing dimensioned quantities in the answer then you also need units. You don't need units for m and g since symbolic variables encapsulate the physical quantity independently of units. So you just need the right units for the 1/19.6 factor. What would those be?
For part b), you have used the same symbol v for two different velocities, the terminal velocity and the initial velocity. So, yes, you should have substituted mg/19.6 (with units) for k.
The problem is the lack of units for the 19.6. What units should that have? So what units will the 1/19.6 have?ZenchiT said:Would it have N as the units because it has the same dimensions as force?
m/s^-1 as its terminal velocity?haruspex said:The problem is the lack of units for the 19.6. What units should that have? So what units will the 1/19.6 have?
m/s, or ms-1 (but not m/s-1) is right for the 19.6. So what should it be for 1/19.6?ZenchiT said:m/s^-1 as its terminal velocity?
Thank you for the amount of help you've given me!
Well, surely that is incorrect! (sorry to rain on your parade). The initial velocity is given as +6 m/s and your formula says initial velocity = 0!ZenchiT said:Part a) F=mg and F=kv
Therefore mg=kv and v=19.6 (terminal velocity)
k = mg/v
k = mg/19.6
Part b)
Equation of motion -> -mg-kv = ma
(Sub in k =mg/v)
-2mg = ma
a = -2g
dv/dt = -2g
v = -2gt
Or maybe instead of subbing in k=mg/v It should have been mg/19.6?
Voila! Surely that's correct right?!