How Can We Understand Iterated and Double Limits in Complex Variables?

  • Thread starter Thread starter hanson
  • Start date Start date
  • Tags Tags
    Limit
Click For Summary
The discussion focuses on understanding the concepts of iterated limits and double limits in the context of complex variables, particularly in relation to the Cauchy-Riemann equations. An iterated limit involves taking the limit of two independent variables, x and y, in a specific order, while a double limit considers both variables approaching a point simultaneously, without a specified path. The participants clarify that for a complex derivative to exist, the limit must be independent of the path taken, which aligns with the definition of a double limit. They also emphasize that demonstrating a limit's existence often requires showing that it is path-independent, contrasting it with the concept of double limits. The conversation concludes with the understanding that limits in complex analysis treat z as a single entity rather than separate components.
hanson
Messages
312
Reaction score
0
Hello!
I am confused about things about "iterated limit" and "double limit"
I am doing something about complex variables, and learning to derive the Cauchy-Riemann Equation.
The concept of "iterated limit" to me is that, supossing 2 independt variables x&y, it is taking the limit either x first then y or y first then x. Geometrically, it is representing two paths to approach the right destination, right?

But I can't really visualise how "double limit" really work.
What is a double limit? I am told that it is "x and y go togather in any manner"
What does it mean?
I can think of some cases that x and y will approach the destination togather.
Say, the path is y=mx as x->0. In this case, x and y will approach to 0 togather. So, is this a double limit?

If this is, there is also a problem.
There is a statement that "the limit, representing the derivative of a complex function, must exist as a double limit for delta z= delta x+i(delta y) approaching zero."

I don't see why the term "double limit" is used here.

To me, the complex derivative exists when all double limits and all iterated limits gives the same value so that the limit can be said of being independent of any paths. Am I correct?
 
Physics news on Phys.org
hanson said:
Hello!
I am confused about things about "iterated limit" and "double limit"
I am doing something about complex variables, and learning to derive the Cauchy-Riemann Equation.
The concept of "iterated limit" to me is that, supossing 2 independt variables x&y, it is taking the limit either x first then y or y first then x. Geometrically, it is representing two paths to approach the right destination, right?

But I can't really visualise how "double limit" really work.
What is a double limit? I am told that it is "x and y go togather in any manner"
What does it mean?
I can think of some cases that x and y will approach the destination togather.
Say, the path is y=mx as x->0. In this case, x and y will approach to 0 togather. So, is this a double limit?

If this is, there is also a problem.
There is a statement that "the limit, representing the derivative of a complex function, must exist as a double limit for delta z= delta x+i(delta y) approaching zero."

I don't see why the term "double limit" is used here.

To me, the complex derivative exists when all double limits and all iterated limits gives the same value so that the limit can be said of being independent of any paths. Am I correct?
You are correct. The Cauchy-Riemann equations simply impose the restriction that the limit is the same whether \Delta z appraoches zero along the real and imaginary axis. It can be proven that this is enough to guarantee that the limit is the same along all paths in the complex plane.

In terms of a double limit in general, that could mean something like:
\lim_{\substack{x\rightarrow 0\\y\rightarrow 0}} x^y=1
\lim_{\substack{y\rightarrow 0\\x\rightarrow 0}} x^y=0
This really is not the same thing as delta z approaching zero, having real and imaginary parts. z is only one number, and that is how it is treated in the analytic functions of complex analysis. You could write a real number in terms of rational and irrational parts, like: x = a + b\sqrt{2} Then you could take the limit as x approaches zero as only one number, because in real analysis we do not treat functions that perform different operations on the rational and irrational parts. Just so, in complex analysis we deal with functions that treat z as one indivisible entity.
 
Last edited:
don't we need to specific a path for double limit?
 
Don't we need to specify a path for double limit?
like y=mx, x->0, y->0?
And how can the two examples of double limit be calculated?
 
Well, the limit only exists if it is "path independent"

let us fix that we're taking a limit as x,y both tend to 0 of some function f(x,y), let us further suppose that we want to show that limit is zero

then we need to show that for all e>0 there is a d>0 such that for all |(x,y)|<0 that |f(x,y)<0 where | | means distance eg the euclidean distance from the origin.

it is natrually easier to show that a limit does not exist by showing two different paths that have different limits.

however this is a situation when we are talking about (x,y) tends to zero.

this strictly different from a double limit
lim x tends to 0 of lim y tends to 0 of f(x,y)
 
Last edited:
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 27 ·
Replies
27
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
Replies
8
Views
1K
  • · Replies 19 ·
Replies
19
Views
3K
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
11
Views
2K