How Can We Use Calculus to Predict Population Growth?

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Homework Help Overview

The discussion revolves around using calculus to model population growth, specifically through the differential equation \(\frac{dP}{dt} = 0.2P\). The original poster is attempting to derive a formula for population over time given an initial population of 5300.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are exploring the correct manipulation of the differential equation and discussing the process of integration. Questions are raised about the proper arrangement of terms and the interpretation of the equation.

Discussion Status

The discussion is active, with participants providing feedback on each other's interpretations of the equation. Some guidance has been offered regarding the integration process, but there is no explicit consensus on the correct approach yet.

Contextual Notes

There is an emphasis on ensuring that terms are correctly arranged in the differential equation, and participants are questioning the assumptions made in the original poster's approach.

Sirsh
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Hi all, I'm just wondering if this is correct: [tex]\frac{dP}{dt}[/tex] =0.2P If the population is now 5300:
(a) Write a formula for the population in t years time.

To do this would i antidifferntiate 0.2P, so.. (0.2P^2)/2 = 0.1P^2 + t?

Thank you!
 
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No that is wrong. dP and 0.2P are on opposite sides. Rewrite the equation in such a way that all Ps are on the same side and all ts on the other side.
 
dP/0.2P = dt? or dP/P = 0.2dt
 
Both are correct. Now you can integrate both sides of that equation.
 
Um, Does the equation mean that: the derivative of P divided by P equals 0.2 times the derivative of t?
 
No [itex]dP=\frac{dP}{dt} dt[/itex], but as you can see they are very closely related. Just put the integral sign in front of both sides of the equation and it will become clear what to do.
 

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