How can x^0 be equal to 1?

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Discussion Overview

The discussion revolves around the concept of any number raised to the power of zero being equal to one. Participants explore various mathematical definitions, proofs, and reasoning related to this topic, including the implications of defining \(0^0\) and the consistency of exponent rules.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • Some participants propose that \(1 = 4^0\) can be derived from the pattern of exponentiation, illustrating with multiplication.
  • Others argue that exponentials can be defined using logarithms, leading to the conclusion that \(n^0 = e^{0 \ln{n}} = 1\), although some express skepticism about this proof's convincingness.
  • Several participants present the identity \(1 = \frac{a^n}{a^n} = a^{n-n} = a^0\) as a straightforward proof, while others question its validity when \(n = m\).
  • One participant highlights that \(0^0\) is often defined as one for simplicity, but acknowledges that this definition is not universally accepted and can depend on context.
  • Some participants express confusion over the proofs and request further clarification on the reasoning behind them.
  • There is a discussion about the circular reasoning involved in some proofs and whether certain identities should be taken as axioms.
  • Participants note that the original post's conclusion about \(0^0\) being equal to one is contentious and not universally agreed upon.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the proofs presented, with multiple competing views on the validity of different approaches to understanding why any number raised to the power of zero equals one. The discussion remains unresolved regarding the treatment of \(0^0\) and the implications of various proofs.

Contextual Notes

Some proofs rely on definitions that may not hold in all contexts, particularly when dealing with limits or specific cases like \(0^0\). The discussion reflects a range of mathematical reasoning and assumptions that are not universally accepted.

  • #31
neutrino said:
1 = \frac{a^n}{a^n} = a^{n-n} = a^0


What could be more simpler than that?

I think this actually proves it the previous once doesn't really prove it, because you'd need the information above for it. Besides this is such a simple proof and anyone can understand it.
 

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