How Can You Calculate the Ball's Speed Inside an Inverted Cone?

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SUMMARY

The discussion focuses on calculating the speed of a ball rolling inside an inverted cone, defined by parameters such as height (h), vertical distance from the cone's tip to the ball (y), radius (a), and gravitational acceleration (g). The user, Alex, expresses confusion regarding the interpretation of 'a' and its relation to acceleration. Key equations discussed include centripetal acceleration (a = w^2 * r and a = (v^2)/r) and the forces acting on the ball, specifically the normal force and gravitational force. Dorothy clarifies the correct placement of the normal force in the force equations, which is crucial for resolving the x-direction forces accurately.

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abeltyukov
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Hi,

There is an inverted cone with height h. There is a ball rolling around inside creating a horizontal circle. The height from the tip of the inverted cone to the ball is y. a is given from the center of the cone to the outer edge.

The question asks to express the ball's speed in terms of a, h, y, and g.

I am confused as to why a is shown from the center of the cone to the edge. Is a in this case the same as acceleration?

I know a = w^2 * r as well as a = (v^2)/r
I have the forces in the y-direction: N = mg
I have the forces in the x-direction: (h-y)sin(theta) = (mv^2)/r

I believe I am screwing up on the x-direction forces. Any suggestions?


Thank you very much,
Alex
 
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The normal force is perpendicular to the surface. That's not where you put it in your force equation. That will also help you fix the force equations for X.

Dorothy
 

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