Ry122 Messages 563 Reaction score 2 Thread starter Mar 17, 2008 #1 How do you get 3/sqrt2 from 3sqrt2/2?
Math Is Hard Staff Emeritus Science Advisor Gold Member Messages 4,663 Reaction score 37 Mar 17, 2008 #3 hint: sqrt2/sqrt2 = 1
Integral Staff Emeritus Science Advisor Homework Helper Gold Member Messages 7,232 Reaction score 66 Mar 17, 2008 #5 Try going the other way. Start with [tex]\frac 3 {\sqrt 2}[/tex] to get [tex]\frac {3 \sqrt 2} 2[/tex]
Try going the other way. Start with [tex]\frac 3 {\sqrt 2}[/tex] to get [tex]\frac {3 \sqrt 2} 2[/tex]
Feldoh Messages 1,336 Reaction score 3 Mar 17, 2008 #6 If you're going from 3sqrt2/2 to 3/sqrt2 you're basically de-rationalizing the denominator.
HallsofIvy Science Advisor Homework Helper Messages 42,895 Reaction score 983 Mar 18, 2008 #7 By definition [itex](\sqrt{2})^2= \sqrt{2}\sqrt{2}= 2[/itex]. That means that [tex]\frac{\sqrt{2}}{2}= \frac{\sqrt{2}}{\sqrt{2}\sqrt{2}}[/tex]
By definition [itex](\sqrt{2})^2= \sqrt{2}\sqrt{2}= 2[/itex]. That means that [tex]\frac{\sqrt{2}}{2}= \frac{\sqrt{2}}{\sqrt{2}\sqrt{2}}[/tex]
Air Messages 202 Reaction score 0 Mar 21, 2008 #8 Ry122 said: How do you get 3/sqrt2 from 3sqrt2/2? [itex]\frac{3}{\sqrt 2} . \frac{\sqrt 2}{\sqrt 2} = \frac{3 \sqrt 2}{2}[/itex]. This is rationalising the denominator as you cannot have a surd on the denominator. The question that you are asking is how you get the reverse, de-rationalising the denominator. Try opposite steps to the one I shown.
Ry122 said: How do you get 3/sqrt2 from 3sqrt2/2? [itex]\frac{3}{\sqrt 2} . \frac{\sqrt 2}{\sqrt 2} = \frac{3 \sqrt 2}{2}[/itex]. This is rationalising the denominator as you cannot have a surd on the denominator. The question that you are asking is how you get the reverse, de-rationalising the denominator. Try opposite steps to the one I shown.