How can you de-rationalise the denominator of 3sqrt2/2?

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Ry122
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How do you get 3/sqrt2 from 3sqrt2/2?
 
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Try going the other way.
Start with
[tex]\frac 3 {\sqrt 2}[/tex]

to get

[tex]\frac {3 \sqrt 2} 2[/tex]
 
If you're going from 3sqrt2/2 to 3/sqrt2 you're basically de-rationalizing the denominator.
 
By definition [itex](\sqrt{2})^2= \sqrt{2}\sqrt{2}= 2[/itex]. That means that
[tex]\frac{\sqrt{2}}{2}= \frac{\sqrt{2}}{\sqrt{2}\sqrt{2}}[/tex]
 
Ry122 said:
How do you get 3/sqrt2 from 3sqrt2/2?

[itex]\frac{3}{\sqrt 2} . \frac{\sqrt 2}{\sqrt 2} = \frac{3 \sqrt 2}{2}[/itex].

This is rationalising the denominator as you cannot have a surd on the denominator. The question that you are asking is how you get the reverse, de-rationalising the denominator. Try opposite steps to the one I shown.