- #1
mileena
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Hi, I know how to rationalize a denominator when it is a square root monomial or a square root binomial (through conjugation).
For example, for a square-root monomial:
5/√25 =
[5(√25)]/
[(√25)(√25)] =
[5(√25)]/25 =
(√25)/5 =
1 or -1and, for a square-root binomial:
5/(5 + √25) =
5(5 - √25)/
[(5 + √25)(5 - √25)] =
[5(5 - √25)]/
25 -25 =
0/0 [undefined] or 50/0 [undefined] But what if the denominator is a cube root:
x/(3√11) ?
How do you simplify this (assuming the denominator isn't a perfect cube)? I didn't get a question similar to this correct on my assessment test.
Thanks!
For example, for a square-root monomial:
5/√25 =
[5(√25)]/
[(√25)(√25)] =
[5(√25)]/25 =
(√25)/5 =
1 or -1and, for a square-root binomial:
5/(5 + √25) =
5(5 - √25)/
[(5 + √25)(5 - √25)] =
[5(5 - √25)]/
25 -25 =
0/0 [undefined] or 50/0 [undefined] But what if the denominator is a cube root:
x/(3√11) ?
How do you simplify this (assuming the denominator isn't a perfect cube)? I didn't get a question similar to this correct on my assessment test.
Thanks!
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