MHB How Can You Verify the Sum of Roots in a Quadratic Equation?

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To verify the sum of the roots in a quadratic equation ax^2 + bx + c = 0, the roots A and B can be expressed as A = (-b + √(b² - 4ac))/(2a) and B = (-b - √(b² - 4ac))/(2a). Adding these two roots results in the radicals canceling out, simplifying the expression to (-2b)/(2a). This further simplifies to -b/a, confirming the relationship A + B = -b/a. Thus, the theorem regarding the sum of the roots is logically verified through this process.
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Let A and B be roots of the quadratic equation
ax^2 + bx + c = 0. Verify the statement.

A + B = -b/a

What are the steps to verify this statement?
 
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RTCNTC said:
Let A and B be roots of the quadratic equation
ax^2 + bx + c = 0. Verify the statement.

A + B = -b/a

What are the steps to verify this statement?
There is a theorem for this, but let's do it logically. The two solutions, A and B of the quadratic are
[math]A = \frac{-b + \sqrt{b^2 - 4ac}}{2a}[/math] and [math]B = \frac{-b - \sqrt{b^2 - 4ac}}{2a}[/math]

Now add the two. (Hint: What happens to the radicals?)

-Dan
 
topsquark said:
There is a theorem for this, but let's do it logically. The two solutions, A and B of the quadratic are
[math]A = \frac{-b + \sqrt{b^2 - 4ac}}{2a}[/math] and [math]B = \frac{-b - \sqrt{b^2 - 4ac}}{2a}[/math]

Now add the two. (Hint: What happens to the radicals?)

-Dan

The radicals disappear. We are then left with (-2b)/(2a).
Of course, (-2b)/(2a) simplifies to -b/a.
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...

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