How could this,Sigma0 decay into Lambda and gamma, happens?

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SUMMARY

The discussion centers on the electromagnetic decay of the Σ0(1385) baryon into a Λ baryon and a photon (γ), represented by the reaction Σ0→Λ+γ. The author highlights a violation of parity conservation, noting that the intrinsic parity of Σ0 is even, while the combined parity of Λ and γ is odd. The conversation emphasizes the importance of considering both the intrinsic parities of the particles and the parity of the wave-function in determining the overall parity of the final state. The author seeks clarification on calculating the parity of the final state, specifically regarding the parity valued (-1)L, where L is the orbital quantum number.

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HanningWu
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I found an article, titled Electromagnetic Decay of the Σ0(1385) to Λγ , in the arXiv telling that the reaction
Σ0→Λ+γ
can happen through electromagnetic interaction. However, if I examine the conservation of parity. Parity on the left side is even(P(Σ0)=+), but that on the right side is odd(P(Λ)=+, while P(γ)=-). In this sense, the parity conservation is violated. In addition, I am convinced that the parity is conserved under electromagnetic interaction, so this reaction by no means can exist.
 
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Those are the intrinsic parities of the particle states. You also need to consider the parity of the wave-function of the final state.
 
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Orodruin said:
Those are the intrinsic parities of the particle states. You also need to consider the parity of the wave-function of the final state.
Thank you so much! Problem solved. :biggrin:
 
Orodruin said:
Those are the intrinsic parities of the particle states. You also need to consider the parity of the wave-function of the final state.
Since I can't simply multiply the parity of the Lambda bayon and the photon, how can I calculate the parity of the final state?
 
You can, but you also have to multiply it with the parity of the wave-function combining the two particles.
 
mfb said:
You can, but you also have to multiply it with the parity of the wave-function combining the two particles.
Does "the parity of the wave-function combining the two particle" mean the parity valued (-1)L, where L is the orbital quantum number?
 

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