How Deep Is the Lake and What Is the Initial Velocity of the Ball?

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SUMMARY

The discussion focuses on a physics problem involving a lead ball dropped from a height of 5.44 meters into a lake, where it hits the water and sinks with constant velocity. The time taken to reach the bottom is 4.84 seconds. The correct approach to solve for the lake's depth involves recognizing that after the ball enters the water, it travels with constant velocity, not under acceleration. The initial velocity required for the ball to reach the bottom in the same time when thrown from the board is calculated using kinematic equations, specifically considering the total distance of 5.44 m plus the lake's depth.

PREREQUISITES
  • Understanding of kinematic equations in physics
  • Knowledge of gravitational acceleration (g = -9.8 m/s²)
  • Concept of constant velocity versus acceleration
  • Ability to solve quadratic equations
NEXT STEPS
  • Study the kinematic equations for uniformly accelerated motion
  • Learn how to calculate distance, velocity, and time in free fall scenarios
  • Explore the effects of drag and buoyancy on objects in fluids
  • Practice solving similar physics problems involving multiple phases of motion
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This discussion is beneficial for physics students, educators, and anyone interested in understanding motion under gravity and fluid dynamics.

lgen0290
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Homework Statement



A lead ball is dropped into a lake from a diving board 5.44 m above the water. It hits the water with a certain velocity and then sinks to the bottom with this same constant velocity. It reaches the bottom 4.84 s after it is dropped. (Assume the positive direction is upward.)
(a) How deep is the lake?


(c) Suppose that all the water is drained from the lake. The ball is now thrown from the diving board so that it again reaches the bottom in 4.84 s. What is the initial velocity of the ball?

Homework Equations


h=.5(g)(t^2)


The Attempt at a Solution



I figured that the ball would fall at -9.8m/s, but that the trip it takes would have to be divided into two parts, as when it hit the surface of the water it would stop for an instant.

I figured 5.44m=.5(-9.8 m/s)(t^2). This gave me 1.05 s(which doesn't sound realistic, but the units cancel out find). I then took the remaining time(3.79 s) and plugged it into get
h=.5(-9.8 m/s)(3.79s^2) and got 70. 38 m.

For the other problem I figured there would be no stop, so I used h=.5(-9.8)(4.84^2) and got 114.74/4.84=23.708 m/s.

What gives?
 
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For question (a),

You are correct that the time it takes for the ball to fall from the diving board to the water surface is 1.05 s (this does make sense, since with g = -9.8 m/s2, a ball starting from rest would fall 4.9 m; 5.44 m is a little more than 4.9 m, so it takes a little longer than 1 s).

However, remember that the problem says that once the ball is inside the water, it travels with constant velocity. That means there is no more acceleration (presumably, the drag from the water will cancel out gravity). Therefore, you would not use -9.8 as your acceleration for the remaining 3.79 seconds.

For problem (c),

This problem depends on your answer to part (a). Currently, you are assuming the initial velocity is 0 and calculating h, which is how far the ball would travel. Actually, you know how far the ball has to travel. It is 5.44 m + the depth of the lake.

Instead, the question asks you what the initial velocity has to be for the ball to fall, always under the acceleration of gravity, g = -9.8 m/s2, the distance 5.44 m + depth of lake in 4.84 s. You know the time of travel, the distance the ball must move, and the constant acceleration, and you are asked to find initial velocity. Which of your four kinematic equations should you use?
 

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