How Deep Will a Less Dense Ball Sink in Water?

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    Bouyancy Motion
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SUMMARY

The discussion focuses on calculating the depth to which a less dense ball (density of 0.4*103 kg/m3) sinks in water after falling from a height of 9 cm. The participant initially calculated the final velocity and retarding force due to buoyancy but overlooked the weight of the ball in their calculations. Upon realizing that the buoyant force must counteract the weight of the ball, they corrected their approach, leading to the conclusion that the ball sinks to a depth of 2.25 cm, which corresponds to option (d).

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  • Basic understanding of density calculations (Density = Mass / Volume)
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Homework Statement



A ball whose density is 0.4*103 kg/m3 falls into water from a height of 9cm. To what depth does the ball sink? Only consider bouyancy and ignore retardation due to viscocity.

(a) 9cm (b) 6cm (c) 4.5cm (d) 2.25cm

Homework Equations



buoyant force = Volume of Body*Density of Liquid*Gravitational Acceleration

v2 = u2 + 2as

F = ma

Density = Mass / Volume


The Attempt at a Solution



Well, first I figured out the final velocity with which the body entered into the water using the third equation of motion (second equation stated above).

Then I figured out the retarding force acting on the body because of the bouyancy offered by the water (using the second, the first, and then the third equation stated above).

Finally I plugged in the retardation offered by bouyancy into the third equation of motion, and figured out the final answer. My answer was 3.6cm, but that is nowere in the answer choices.

Please help.
 
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In the retardation equation, did you include the fact that the ball's weight is still acting downwards on it, and that the retardation is caused by a resultant upwards force equal to buoyancy minus weight?
 
Umm... no I didn't. I'm stuipid, right?

Yup, well that solved the problem.

Thanks a lot.
 

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