How did this conversion took place ?

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Homework Help Overview

The discussion revolves around the transformation of a mathematical expression, specifically the relationship between the expressions 6(2)^(n-2) + 1 and 6(2)^(n-1) + n + 2. Participants are trying to understand how the second expression can be derived from the first within the context of sequences and series.

Discussion Character

  • Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Some participants attempt to clarify the nature of the expressions, noting that they are not equations. Others question the validity of the transformation and suggest checking specific values of n to illustrate differences between the expressions.

Discussion Status

The discussion is ongoing, with participants exploring the definitions and relationships between the expressions. There is a request for further clarification on the original problem context, and some participants are seeking additional resources to aid understanding.

Contextual Notes

One participant references a textbook for context, indicating that the expressions are part of a larger problem related to sequences and series. However, access to the referenced material appears to be problematic for some participants.

Sumedh
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Homework Statement


6(2)^(n-2) +1

then summation of above equation will be
6(2)^(n-1) + n + 2

can you please tell me how this equaton came from the first equation?

The Attempt at a Solution



the later formula is correct summation of the former

because it may look that the summation is
6(2)^(n-1) +n - 3

but by putting values of n-
6(2)^(n-1) +n - 3 is incorrect

please help as how the topmost formula gives the second formula
 
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Sumedh said:

Homework Statement


6(2)^(n-2) +1

then summation of above equation will be
6(2)^(n-1) + n + 2

can you please tell me how this equaton came from the first equation?
It doesn't. First off, these aren't equations - they are expressions. An equation is a statement that two expressions are equal, and always has an = symbol in it.

Starting from your first expression,
6\cdot2n-2 + 1 = 6\cdot2n-1\cdot(1/2) + 1 = 3\cdot2n-1 + 1

To show that your two expressions above aren't identically equal, let n = 2. Then 6\cdot2n-2 + 1 = 6 * 1 + 1 = 7.

And 6\cdot2n-1 + n + 2 = 6* 2 + 2 + 2 = 16.

Sumedh said:

The Attempt at a Solution



the later formula is correct summation of the former

because it may look that the summation is
6(2)^(n-1) +n - 3

but by putting values of n-
6(2)^(n-1) +n - 3 is incorrect

please help as how the topmost formula gives the second formula
 
I'm not sure what these expressions (and these are expressions, not equation) are. Are there any symbols missing? Can you attach an image, or retype using LaTeX?
 
I get a "page is unavailable" error.
 

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