How do 6 quarks manifest hiden SU(2) symmetry(together SU(3) symmetry)?

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SUMMARY

The discussion centers on the manifestation of hidden SU(2) symmetry in the context of six quarks and their relationship with lepton families. It is established that leptons exhibit broken SU(2) symmetry, where each lepton family consists of a massive state (electron) and a nearly massless state (neutrino). The participant seeks clarification on how hidden SU(2) symmetry operates among the six quarks, which are organized into three flavor families, each demonstrating flavor symmetry SU(2). The interaction of hadrons through electroweak and strong forces is also acknowledged.

PREREQUISITES
  • Understanding of SU(2) and SU(3) symmetries in particle physics
  • Familiarity with the Standard Model of particle physics
  • Knowledge of quark flavors and their interactions
  • Basic concepts of electroweak and strong interactions
NEXT STEPS
  • Study the implications of SU(2) symmetry in the Standard Model
  • Research the role of quark flavor symmetry in particle interactions
  • Explore the relationship between electroweak and strong forces in hadrons
  • Learn about the mass generation mechanism for leptons and quarks
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Particle physicists, students of theoretical physics, and anyone interested in the symmetries governing fundamental particles and their interactions.

ndung200790
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Please teach me this:
It seem to me that lepton manifests broken symmetry SU(2) with couple electron and neutrino(electron is a state with mass,neutrino is a state with nearly zero mass).Similarly for 2 other families of lepton,we have a state with mass and a state with nearly zero mass.But I do not understand how does hiden SU(2) symmetry manifest with 6 quarks,because the hadrons have electro-weak interaction and strong interaction.
Thank you very much in advance.
 
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At the moment I know that 6 quarks form 3 ''flavor'' families(example the couple up and down quarks is a ''flavor'' family) that manifest the ''flavor'' symmetry SU(2).Is that correct?
 

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