Josiah
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- How do bar detectors work
Hi, I was just wondering how bar detectors work. From what Ive read, the electrons act as one, thus accentuates the effect of a single gravitational wave.
What have you read? Please give specific references.Josiah said:From what Ive read
I think our guy is talking about Weber Bars. A precursor to LIGO, without lasers.Ibix said:Don't they just change length when a gravitational wave passes through them? And you should be able to detect the induced strains with sufficiently sensitive strain gauges. Not sure where electrons come into this.
Unless there's some other kind of bar detector I've not heard of.
Yes, and I think that's exactly what @Ibix is talking about as well. To quote his post #4, with some clarifications in brackets added by me:AlexB23 said:I think our guy is talking about Weber Bars. A precursor to LIGO, without lasers.
As @renormalize says, I know that. Interferometric detectors like LIGO have mirrors that are free to move independently, so they don't resist length changes and you can use interferometry to detect those changes as the gravitational wave passes through. Solid bars do resist length changes, so should ring (similar to the way they do when tapped by a hammer, but much, much weaker) when a gravitational wave passes through. But electrons don't really enter into the discussion any more than they do in any other material science topic.AlexB23 said:I think our guy is talking about Weber Bars. A precursor to LIGO, without lasers.
https://en.wikipedia.org/wiki/Weber_bar
What I do know is that the OP was vague. Bar detector does not return any results, unless one specifies Weber Bars.renormalize said:Yes, and I think that's exactly what @Ibix is talking about as well. To quote his post #4, with some clarifications in brackets added by me:
"Don't they [Weber bars made of metal, e.g., aluminum] just change length when a gravitational wave passes through them? And you should be able to detect the induced strains [in the block of metal, caused by the passage of the wave] with sufficiently sensitive strain gauges. Not sure where electrons come into this [i.e., the block is just ordinary, room-temperature metal involving no special electron states other than standard conduction]."