How Do Buoyant Forces Affect Submerged Objects?

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SUMMARY

This discussion focuses on the principles of buoyant forces affecting submerged objects, specifically a 100-gram metal chunk with a density of 4 grams per cubic centimeter. The mass of water displaced by the metal is calculated using the formula for density (d=m/v), resulting in a displacement of 0.025 kg. The buoyant force is determined by the weight of the displaced water, calculated as 250 Newtons using the formula for buoyant force (weight of fluid displaced = volume of object * density of fluid * gravity). The final reading on the spring scale when the metal is submerged is also derived from these calculations.

PREREQUISITES
  • Understanding of density and its calculation (d=m/v)
  • Knowledge of buoyant force principles
  • Familiarity with Newton's laws of motion
  • Basic skills in unit conversion (grams to kilograms)
NEXT STEPS
  • Study Archimedes' principle in detail
  • Learn about the relationship between buoyancy and density
  • Explore the concept of hydrostatic pressure
  • Investigate applications of buoyant forces in engineering
USEFUL FOR

Students studying physics, particularly those focusing on fluid mechanics, as well as educators and anyone interested in the practical applications of buoyant forces in real-world scenarios.

dragon162
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Homework Statement


note: It may make things easier to assume that g=10 m/s^2
Suppose that I have a 100 gram chunk of metal with a density of 4 grams per cubic centimeter.
1)What is the mass of water displaced by this chunk of metal?(give your answer in kg)
2)what is the buoyant force on the metal?
3)If I hang this 100 gram chunk of metal from a spring scale and lower the metal into the water what will the scale read?(give your answer in Newtons)


Homework Equations


d=m/v
S=W/(W-W_0)
S=W/(W_1-W_2)

The Attempt at a Solution



For number one I am guessing its just a simple d=m/v problem. So given the information V=0.1kg/.004 kg/cm^3= 25. But i am not sure what to do with this after.

For number two I know that the difference of the weight of the object in the air and the weight of the object when its fully submerged in water is the buoyant force exerted on the body by the water. So to get the W=mg=.1kg*10m/s^2 but i am not sure how to get W_1= the weight of the object in the water.

for part three I am just not sure what I am supposed to do.
 
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ok so i figured out for part two that the volume of the object is the same as the volume of the displaced water. so using the v olume i calculated i used m=dv=25(1)=25 to get the mass of the water. This correct?

as for part two, i found out that the buoyant force= to the weight of fluid displaced and to find the weight of fluid displaced its just volume of object* density of the fluid*gravity
so 25*1*10=250. Is this correct as well?

still trying to figure out part three so any help would be appreciated.
 
bump, some help please
 

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