How do Cooper pairs carry a current with zero net-momentum?

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SUMMARY

The discussion centers on the mechanism by which Cooper pairs in superconductors carry a current despite having a net momentum of zero. It clarifies that Cooper pairs consist of electrons with opposite spins rather than opposite momenta, allowing for a finite supercurrent. The confusion arises from conflating linear momentum with electron spin, as the electrons in Cooper pairs can still contribute to current flow even when their individual momenta are negligible. This concept is elaborated in Schrieffer's "Theory of Superconductivity."

PREREQUISITES
  • BCS theory of superconductivity
  • Understanding of Cooper pairs and electron pairing
  • Basic quantum mechanics concepts, particularly momentum and spin
  • Knowledge of superconductive versus non-superconductive electron behavior
NEXT STEPS
  • Read Schrieffer's "Theory of Superconductivity" for in-depth understanding
  • Explore the relationship between electron spin and momentum in quantum systems
  • Investigate the implications of Cooper pair dynamics on superconductivity
  • Study the differences between superconductive and non-superconductive electron movement
USEFUL FOR

Physicists, electrical engineers, and students studying quantum mechanics or superconductivity will benefit from this discussion, particularly those interested in the behavior of Cooper pairs and their role in supercurrents.

alberliu
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TL;DR
How do Cooper pairs carry a current with zero net-momentum?
One of the first starting points of introducing BCS theory in a superconductor is applying a theorem stating that the ground-state of a quantum system has an expectation value for its momentum of zero. You then use this to say that an electron must pair with another electron of equal and opposite momentum to form a Cooper pair.

If this is the case, how does this zero-momentum state result in a finite supercurrent? Maybe this is a frame-of-reference issue, but it's not clear to me how you get net charge movement in one direction with a net momentum of zero.
 
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That's simply not true. In a state with finite current, the Cooper pairs don't have finite momentum and the electrons in a pair don't have exactly opposite momentum. In the book by Schrieffer "Theory of superconductivity", this is explained in detail.
 
alberliu said:
Summary:: How do Cooper pairs carry a current with zero net-momentum?

One of the first starting points of introducing BCS theory in a superconductor is applying a theorem stating that the ground-state of a quantum system has an expectation value for its momentum of zero. You then use this to say that an electron must pair with another electron of equal and opposite momentum to form a Cooper pair.

If this is the case, how does this zero-momentum state result in a finite supercurrent? Maybe this is a frame-of-reference issue, but it's not clear to me how you get net charge movement in one direction with a net momentum of zero.
I think you've mistaken electron spin with linear momentum. The Cooper pairs are of electrons with opposite spins, not opposite momenta. Now, the electrons will be very close to absolute zero, so their linear momenta will be very close to zero as well, but it's not a requirement that they stay at zero momentum once they've already paired up.

Electricity is actually a very slow movement of electrons in non-superconductive situations, but in superconductive situations, it's likely just as slow if not slower, but it's not the individual electron speeds that matter but the overall movement of a mass of electrons that give you your power.
 

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