How do dark spot and tiny hole filters affect Fourier optics images?

  • Thread starter Thread starter George444fg
  • Start date Start date
  • Tags Tags
    Fourier Optics
Click For Summary
Dark spot and tiny hole filters significantly impact Fourier optics images by altering the frequency components of the light used in imaging. The tiny hole filter eliminates high-frequency light, resulting in a limited but clear image by focusing on low-frequency components. Conversely, the dark spot filter removes the concentrated beam, allowing only high-frequency diffracted and refracted beams, which leads to a less clear image. The discussion emphasizes the importance of understanding these filtering processes theoretically, alongside practical experimentation. Overall, the filtering techniques directly influence image clarity and detail in Fourier optics.
George444fg
Messages
25
Reaction score
4
Homework Statement
George44fg
Relevant Equations
Fourier Transform Equations
I was assigned an experiment of Fouriers optics where I have to use different Filters. One of them was the dark spot and the tiny hole. As of my understanding, for tiny hole, we cut off all high-frequency light related to diffraction and refraction, thus using only the low freuency part of the initial image. The result would be a limited yet very clear image on the screen. While for the black spot we cut off the concentrated beam and project only the high frequency diffracted and refracted beams. Thus we get a rather unclear image? Thank you in advance
 
Physics news on Phys.org
How about you run the experiment and then any problems or results you have can be discussed if needed?
 
Tom.G said:
How about you run the experiment and then any problems or results you have can be discussed if needed?
I've already done the experiment, and everything is fine. However, I would like to be sure about the theoretical understanding of the filtering process.
 
George444fg said:
Homework Statement:: George44fg
Relevant Equations:: Fourier Transform Equations

...for tiny hole, we cut off all high-frequency light related to diffraction and refraction, thus using only the low freuency part of the initial image.

...the black spot we cut off the concentrated beam and project only the high frequency diffracted and refracted beams.

I agree!
 
Tom.G said:
I agree!
I thank you a lot.
 
If have close pipe system with water inside pressurized at P1= 200 000Pa absolute, density 1000kg/m3, wider pipe diameter=2cm, contraction pipe diameter=1.49cm, that is contraction area ratio A1/A2=1.8 a) If water is stationary(pump OFF) and if I drill a hole anywhere at pipe, water will leak out, because pressure(200kPa) inside is higher than atmospheric pressure (101 325Pa). b)If I turn on pump and water start flowing with with v1=10m/s in A1 wider section, from Bernoulli equation I...

Similar threads

Replies
6
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K
Replies
7
Views
7K
Replies
1
Views
3K
  • · Replies 9 ·
Replies
9
Views
8K
  • · Replies 1 ·
Replies
1
Views
10K
  • · Replies 29 ·
Replies
29
Views
7K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 9 ·
Replies
9
Views
3K
Replies
13
Views
7K