How Do I Apply Stolz-Cesaro Theorem to Find the Limit of a Sequence?

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To find the limit of the sequence (xn) = (cos(π/n+1) + cos(π/n+2) + ... + cos(π/2n))/n as n approaches infinity, the Stolz-Cesaro theorem is suggested for application. The limit expression derived is the limit of cos(π/2n+1) + cos(π/2n+2) - cos(π/n+1). Clarification is needed regarding the intended terms in the limit expression, as there may be a misunderstanding in notation. Additionally, to properly apply the Stolz-Cesaro theorem, a corresponding sequence must be identified. The discussion emphasizes the importance of correctly setting up the sequences involved in the theorem's application.
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Homework Statement


hello, i have to find the limit of the next array

(xn)=(cos (π/n+1) + cos (π/n+2) + ...+ cos ( π/2n))/n
when n goes to infinity.

Homework Equations


I was told to apply stolz cesaro and that is where i ended up :
the limit is :

limit of cos ( π/2n+1) + cos (π/2n+2) -cos (π/n+1)

The Attempt at a Solution


How i finish this ?
 
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LazuRazvan said:

Homework Statement


hello, i have to find the limit of the next array

(xn)=(cos (π/n+1) + cos (π/n+2) + ...+ cos ( π/2n))/n
What you wrote in the first term was ##\cos(\frac{\pi}{n} + 1)##, and similar in the other two terms. Is that what you intended?
LazuRazvan said:
when n goes to infinity.

Homework Equations


I was told to apply stolz cesaro and that is where i ended up :
the limit is :

limit of cos ( π/2n+1) + cos (π/2n+2) -cos (π/n+1)
Same comment as above.

Also, to apply Stolz-Cesaro (https://en.wikipedia.org/wiki/Stolz–Cesàro_theorem), you need to use it with another sequence. What's the other sequence you are using?
LazuRazvan said:

The Attempt at a Solution


How i finish this ?
 
Last edited:
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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