The discussion revolves around calculating percentage increases for ratios in mathematical problems. The original poster presents two scenarios involving ratios: one related to a photocopier's increase in paper and another concerning the composition of an alloy. Participants are exploring how to correctly interpret and calculate percentage increases based on these ratios.
Some participants have provided feedback on the calculations, indicating correctness for the first question while expressing uncertainty about the second. There is an ongoing exploration of the assumptions and definitions related to the ratios, particularly concerning the alloy and lead comparison.
There is confusion regarding the presentation of the problem, particularly how the alloy is referred to both as a whole and as a part of the ratio. This has led to questions about the correct interpretation of the ratios involved.
Yes, this is correct.asmalik12 said:Homework Statement
1. A photocpier increases the paper with the ratio 4:5, what % is the paper increased
2. An alloay has a copper, alloy and lead with the ratio 5:7:3, what % is the alloy to lead
2. The attempt at a solution
1. Difference in equation = 5 - 4 = 1
= 1/4 * 100
= 25 %
No. There are 7 parts alloy to 3 parts lead, so there is about 2.33 times as much alloy as lead.asmalik12 said:2. Difference between the ratio of alloy and lead = 7 - 3 = 4
= 4/7 * 100
= 57.14 %
Am I doing it rightly?